KMnO4±ê×¼ÈÜÒºµÎ¶¨Fe2+£¬Æä»¯Ñ§¼ÆÁ¿µãµÄµçÊÆÖµÊÇ £¨ C £© A. 0.73V; B. 0.89V£» C. 1.32V£» D. 1.49V£»
13. ÔÚº¬ÓÐÉÙÁ¿Sn2+µÄFeSO4ÈÜÒºÖУ¬ÓÃK2Cr2O7·¨²â¶¨Fe2+£¬Ó¦ÏÈÏû³ýSn2+µÄ¸ÉÈÅ£¬Ò˲ÉÓõÄÊÇ £¨ D £©
A. ¿ØÖÆËá¶È·¨£» B. ÅäλÑڱη¨ C. ³ÁµíµÎ¶¨·¨£» D. Ñõ»¯»¹ÔÑڱ稣» 14. ÔÚH3PO4¡ªHCl»ìºÏËáÈÜÒºÖУ¬ÓÃ0.1000mol/L K2Cr2O7µÎ¶¨Fe2+ÈÜÒº£¬Æä»¯Ñ§¼ÆÁ¿µãµÄµçÊÆÎª0.86v£¬¶Ô´ËµÎ¶¨×îºÏÊʵÄָʾ¼ÁÊÇ £¨ A £© A. ¶þ±½°·»ÇËáÄÆ£¨E0 ?=0.84V£©£» B. ÁÚ¶þµª·Æ¡ªÑÇÌú£¨E0 ?=1.06V£©£» C. ¶þ±½°·£¨E0 ?=0.76V£©£» D. Ïõ»ùÁÚ¶þµª·ÆÑÇÌú£¨E0 ?=1.25V£©£» 15.£¨ C £©Ó°Ïì³ÁµíµÄÈܽâ¶È
A. ±íÃæÎü¸½£» B. ¹²³Áµí£» C. ÑÎЧӦ£» D. ºó³Áµí£»
16. Ħ¶û·¨²â¶¨Cl-º¬Á¿Ê±£¬ÒªÇó½éÖʵÄpHÖµÔÚ6.5~10.0·¶Î§ÄÚ¡£ÈôËá¶È¹ý¸ß£¬ÔòÒýÆðµÄºó¹ûÊÇ £¨ B £© A. AgCl³Áµí²»ÍêÈ«£» B. Ag2CrO4³Áµí²»Ò×Ðγɣ» C. AgCl³ÁµíÒ×½ºÈÜ£» D. AgCl³ÁµíÎü¸½Cl-ÄÜÁ¦ÔöÇ¿£» 17. ·ð¶û¹þµÂ·¨²â¶¨Cl-ʱ£¬ÒýÈ븺Îó²îµÄ²Ù×÷ÊÇ£¨ A £©
A. ÖÕµãÂÔÍÆ³Ù£» B. AgNO3µÄ±êʾŨ¶È½ÏÕæÊµÖµÂԵͣ» C. ÖÕµãÂÔÌáǰ£» D. ÊÔÒºÖдøÈëÉÙÁ¿µÄBr-£»
18. Ó÷¨Ñï˾·¨²â¶¨Â±»¯Îïʱ£¬ÎªÊ¹µÎ¶¨ÖÕµã±äÉ«Ã÷ÏÔ£¬ÔòÓ¦¸Ã £¨ C £© A. ʹ±»²âÀë×ÓµÄŨ¶È´óЩ£» B. ±£³ÖÈÜҺΪËáÐÔ£» C. ±Ü¹â£» D. ʹ½ºÁ£¶Ôָʾ¼ÁµÄÎü¸½ÄÜÁ¦´óÓÚ¶Ô±»²âÀë×ÓµÄÎü¸½ÄÜÁ¦£» 19. ÏÂÁÐÒªÇóÖв»ÊôÓÚÖØÁ¿·ÖÎö¶Ô³ÆÁ¿ÐÎʽµÄÒªÇóµÄÊÇ £¨ B £© A. Ïà¶ÔĦ¶ûÖÊÁ¿Òª´ó£» B. ±íÃæ»ýÒª´ó£»
C. ÒªÎȶ¨£» D. ×é³ÉÒªÓ뻯ѧʽÍêÈ«·ûºÏ£» 20. ¾§ÐγÁµíµÄ³ÁµíÌõ¼þÊÇ £¨ C £© A. Ũ¡¢Àä¡¢Âý¡¢½Á¡¢³Â£» B. Ï¡¡¢ÈÈ¡¢¿ì¡¢½Á¡¢³Â£» C. Ï¡¡¢ÈÈ¡¢Âý¡¢½Á¡¢³Â£» D. Ï¡¡¢Àä¡¢Âý¡¢½Á¡¢³Â£»
1£¬ ·ÖÎö²âÊÔÖеÄżȻÎó²î£¬¾Íͳ¼Æ¹æÂÉÀ´½²£¬ÆäÕýÈ·µÄ˵·¨ÊÇ£º(BCE)
AÊýÖµ¹Ì¶¨²»±ä¡£ BÊýÖµËæ»ú±ä»¯¡£ C´óÎó²î³öÏֵļ¸ÂÊ´ó
DÕýÎó²î³öÏֵļ¸ÂÊ´óÓÚ¸ºÎó²î¡£
EÊýÖµÏàµÈµÄÕý¡¢¸ºÎó²î³öÏֵļ¸ÂÊÏàµÈ¡£
-1
2£¬ ÒÔK2Cr2O7²â¶¨Ìú¿óʯÖÐFeº¬Á¿Ê±£¬ÓÃ0.02 mol¡¤L K2Cr2O7ÉèÊÔº¬ÌúÒÔFe2O3¼ÆÔ¼Îª
50%£¬ÔòÊÔÑù³ÆÈ¡Á¿Ó¦Îª£º£¨M Fe2O3=159.7g/mol£© ( D)
A £¬0¡£1g×óÓÒ B£¬0¡£2g×óÓÒ C£¬1g×óÓÒ D£¬0¡£4-0¡£6g×óÓÒ E£¬ 0¡£2-0¡£3g×óÓÒ
3£¬ ÔÚº¬ÓÐÉÙÁ¿Sn2+µÄFeSO4ÈÜÒºÖУ¬ÓÃK2Cr2O7²â¶¨Fe2+,Ó¦ÏÈÏû³ýSn2+Àë×ӵĸÉÈÅ£¬×î³£
11
Óõķ½·¨ÊÇ£ºD
A¿ØÖÆËá¶È·¨°¸ B ÂçºÏÑڱη¨°¸ C³Áµí·ÖÀë·¨ D Ñõ»¯»¹ÔÑڱη¨°¸ E Àë×Ó½»»»·¨
-1-1
4£¬ ÓÃ0.1 mol¡¤LNaOHµÎ¶¨0.1 mol¡¤LHAC£¨pKa=4.7£©Ê±µÄpHͻԾ·¶Î§Îª7.7-9.7¡£ÓÉ
-1-1
´Ë¿ÉÒÔÍÆ¶ÏÓÃ0.1 mol¡¤LNaOHµÎ¶¨pKaΪ3.7µÄ0.1 mol¡¤LijһԪÈõËáµÄpHͻԾ·¶Î§ÊÇ£ºB
A£¬6.7-6.8 B,6.7-9.7 C,6.7-10.7 D,7.7-9.7 E,7.7-10.7
5,ÏÂÁÐÕâЩÑÎÖУ¬Äļ¸ÖÖ²»ÄÜÓñê׼ǿËáÈÜÒºÖ±½ÓµÎ¶¨£¿CD COOK -3-6
AÁÚ±½¶þ¼×ËáÇâ¼Ø£¨ COOH £©Ka1=1.1¡Á10 ,Ka2=3.9¡Á10£©
-10
B Na2B4O7¡¤10H2O(H3BO3 Ka=5.8¡Á10)
-5
C NaCA (HCA Ka=1.8¡Á10)
-4
D HCOONa (HCOOH Ka=1.8¡Á10)
-2..12-7.2-12.38
E Na3PO4 (H3PO4 Ka1=10,Ka2=10,Ka3=10) 6ÁÐÄÄЩҪÇó²»ÊÇÖØÁ¿·ÖÎö¶Ô³ÆÁ¿ÐÎʽµÄÒªÇó£ºAC
A ±íÃæ»ýÒª´ó B Ïà¶Ô·Ö×ÓÖÊÁ¿Òª´ó C ¿ÅÁ£Òª´Ö´ó D ÒªÎȶ¨ E ×é³ÉÒªÓ뻯ѧʽ·ûºÏ 7£¬¶ÔEDTAµÎ¶¨·¨ÖÐËùÓõĽðÊôÀë×Óָʾ¼Á£¬ÒªÇóËüÓë±»²â½ðÊôÀë×ÓÐγɵÄÂçºÏÎïÌõ¼þÎȶ¨³£ÊýK¡¯Min:B
-8
A >K¡¯MY B < K¡¯MY C ¡Ö¡¯MY D >10 E >100 K¡¯MY
8£¬Ê¾²î·Ö¹â¹â¶È·¨ºÍÆÕͨ·Ö¹â¹â¶È·¨µÄ²»Í¬ÔÚÓڲαÈÈÜÒºµÄ²»Í¬£¬Ç°ÕߵIJαÈÈÜÒºÊÇ£»D
A ŸAÁóË® B ÈܼÁ C È¥Àë×ÓË® D ±È²âÊÔҺŨ¶ÈÉԵ͵ıê×¼ÈÜÒº E ±È²âÊÔÒºÉԸߵıê×¼ÈÜÒº
1£¬ ¿ÉÒÔÓÃÏ·¨ÖÐÄÇÖÖ·½·¨¼õÉÙ·ÖÎö²âÊÔÖдóżȻÎó²î£ºE
A ½øÐжÔÕÕʵÑéÊÒ B ½øÐпհ×ʵÑéÊÒ C ½øÐÐÒÇÆ÷У׼ D ½øÐзÖÎö½á¹ûУÕý EÔö¼ÓƽÐÐʵÑéµÄ´ÎÊý
-1
2,ÒÑÖªÁÚ±½¶þ¼×ËáÇâ¼Ø£¨KHC8H4O4£©Ä¦¶ûÖÊÁ¿Îª204.2g/mol£¬ÓÃËüÀ´±ê¶¨0.1mol¡¤LNaOH ÈÜÒº£¬Ó¦³ÆÈ¡ÁÚ±½¶þ¼×ËáÇâ¼ØµÄÖÊÁ¿Îª£¨E £©
A£®0.25g×óÓÒ B.1g×óÓÒ C.0.1g×óÓÒ D.0.05g×óÓÒ E.0.5g×óÓÒ
-1-1
3Ó÷¨0¡£1moL¡¤LNaOHµÎ¶¨pKaΪ´Ë3¡£7µÄ0.10 mol¡¤LijһÈõËáµÄpHͻԾ·¶Î§ÊÇ£ºB A 6.7-8.7 B 6.7-9.7 C 6.7-10.7 D 7.7-9.7 E7.7-10.7
-1-1
4,ÔÚH3PO4´æÔÚϵÄHClÈÜÒºÖУ¬ÓÃ0¡£1moL¡¤L K2Cr2O7ÈÜÒºµÎ¶¨µÄ0.1mol¡¤L Fe2+ÈÜÒº£¬Æä»¯Ñ§¼ÆÁ¿µãµÄµçλΪ¼Ñ86V£¬¶Ô´ËµÎ¶¨×îÊÊÒËָʾ¼ÁΪ£»C A ´Î¼×»ùÀ¶£¨¦Õ
¦È¡®
=0¡£36V£© B ¶þ±½°·£¨¦Õ
¦È¡®
¦È¡®
=0¡£76V£©
¦È¡®
C ¶þ±½°·»ÇËáÄÆ£¨¦Õ=0¡£84V£© D ÁÚ¶þµª·Æ-ÑÇÌú£¨¦Õ
¦È¡®
=1¡£06V£©
E Ïõ»ùÁÚ¶þµª·Æ-ÑÇÌú£¨¦Õ=1¡£25V£©
5,ÔÚEDTAÂçºÏµÎ¶¨ÖУ¬ÏÂÁÐÓйØËáЧӦµÄÐðÊö£¬ºÎÕßÊÇÕýÈ·µÄ£¿B
A ËáЧӦϵÊýÓú´ó£¬ÂçºÏÎïµÄʵ¼ÊÎȶ¨ÐÔÓú´ó¡£ B ËáЧӦϵÊýÓúС£¬ÂçºÏÎïµÄʵ¼ÊÎȶ¨ÐÔÓúС¡£
12
C pHÖµÓú´ó£¬ËáЧӦϵÊýÓú´ó¡£
D ËáЧӦϵÊýÇúÏߣ¨ÁÖ°îÇúÏߣ©Äܱíʾ³ö¸÷½ðÊôÀë×ÓÄܹ»±»EDTA׼ȷȷ¶¨µÄ×î¸ßÔÊÐípHÖµ¡£
E ËáЧӦ¸Ä±äÁËÂçºÏÎïµÄÎȶ¨³£ÊýKMY¡£
-1+-1
6, ÒÑÖªÔÚ0.10 mol¡¤LAg(NH3)2ÈÜÒºÖУ¬º¬ÓÐÓÎÀëNH3µÄŨ¶ÈΪ0.10 mol?L£¬¼ÆËãÈÜÒº
++37
ÖÐÓÎÀëAgµÄŨ¶È¡££¨Ag-NH3ÂçºÏÎïµÄÀÛ»ýÎȶ¨³£Êý¦Â1=1.7¡Á10£¬¦Â2=1.0¡Á10£©£¨B £©
-8-1-6-1-7-1
A£®1.0¡Á10mol.L B.1.0¡Á10mol.L C.1.0¡Á10mol.L
-9-1-10-1
D. 1.0¡Á10mol.L E.1.0¡Á10mol.L
7, ÏÂÁÐÓйسÁµíÎü¸½µÄÒ»°ã¹æÂÉÖУ¬ÄÄÌõÊDz»¶ÔµÄ£¿CE A Àë×ӵļÛÊý¸ßµÄ±ÈµÍµÄÒ×±»Îü¸½£» B Àë×ÓŨ¶ÈÓú´óÓúÒ×±»Îü¸½£»
C ³ÁµíµÄ¿ÅÁ£Óú´ó£¬Îü¸½ÄÜÁ¦ÓúÇ¿£»
D Äܲ»ÄÜÓë¹¹¾§Àë×ÓÉú³ÉÄÑÈÜÑγÁµíµÄÀë×Ó£¬ÓÅÏȱ»Îü¸½£» EζÈÓú¸ß£¬ÓúÓÐÀûÓÚÎü¸½£»
2+2+
8£¬ ÓÃË«ëê¹â¶È·¨²â¶¨Pb(ÆäĦ¶ûÖÊÁ¿Îª207.2g/mol),Èô40mLÈÜÒºÖк¬ÓÐ 0.1mgPb,ÓÃ1cm±ÈÉ«ÃóÔÚ520nmϲâµÃ͸¹â¶ÈΪ10%£¬Ôò´Ë»¯ºÏÎïµÄĦ¶ûÎü¹âϵÊýΪ£ºD
2 3 4 5 6
A 1.0¡Á10B 1.0¡Á10 C 1.0¡Á10 D 1.0¡Á10 E 1.0¡Á10
1£® ÒÑÖªµç¼«·´Ó¦CrO2-7+14H++6e?2Cr3++7H2O£¬¼ÆËã¸Ãµç¼«µçλµÄÕýÈ·±í´ïʽΪ£ºD
¦Õ=¦Õ+0.059lg[Cr2O7]/[Cr] B, ¦Õ=¦Õ+0.059lgCr2O7/Cr 6 6
¦È¡ä2-¦È¡ä2-23+
C ¦Õ=¦Õ+0.059lg[CrO7][H+] D ¦Õ=¦Õ+0.059lgCr2O7/Cr 6 [Cr3+]2 6
2£® ÓÃEDTAµÎ¶¨½ð¸ÆÀë×Ó£¬ÒÑÖªlgKCaY=10.69,ÊÔ¹À¼ÆµÎ¶¨Ca2+µÄ×î¸ßÔÊÐíËá¶È´óԼΪpHÖµ£ºD
A£®2 B.4 C.6 D.8 E.10
3£® ijѧÉú²â¶¨¿óʯ͵İٷֺ¬Á¿Ê±£¬µÃµ½ÏÂÁнá¹û£º2.50£¬2.53£¬2.55£¬ÓÃ4 d·¨Ôò¹À¼ÆÔٲⶨһ´ÎËùµÃ
·ÖÎö½á¹û²»Ó¦ÆúÈ¥µÄ½çÏÞÊÇ£ºE
A£®2.51~2.55 B.2.53 ¡À0.017 C2.53¡À0.02 D. 2.463~2.597 E. 2.53¡À0.07
4£® ÓÃÖØ¸õËá¼Ø·¨²â¶¨ÌúµÄº¬Á¿£¬³ÆÈ¡Ìú¿óÊÔÑù0.4000g£¬ÈôµÎ¶¨Ê±ËùÏûºÄK2Cr2O7ÈÜÒºµÄºÁÉýÊýÇ¡ºÃµÈ
ÓÚÌúµÃ°Ù·Öº¬Á¿¡£ÎÊÐëÅäÖÆK2Cr2O7ÈÜÒº¶ÔÌúµÄµÎ¶¨¶ÈΪ¶àÉÙ£¿E
A£®0.800g/ml B.0.00600g/ml C.0.00100g/ml D.0.00200g/ml E.0.00400g/ml
5£® µ±pH=5.00ʱ£¬¼ÆËã0.10mol¡¤L-1¶þÔªÈõËáÈÜÒºÖÐHA-µÄŨ¶È£¬£¨H2AµÄKa1=1.0¡Á10-5,Ka2=1.0¡Á10-8£©D
A.0.025mol¡¤L-1 B.0.075mol¡¤L-1 C.0.055mol¡¤L-1D.0.050mol¡¤L-1 E.0.065mol¡¤L-1
A£®
¦È2-3+2¦È2-23+
6£® PH=10.0£¬º¬ÓÐ0.010mol¡¤L-1ÓÎÀëCN-Àë×ÓµÄÈÜÒºÖУ¬Hg2+ÓëEDTAÂçºÏ·´Ó¦µÄÌõ¼þÎȶ¨³£ÊýΪ¶àÉÙ£¿E
¡£
£¨logKHgY=21.7;Hg2+-CN-ÂçºÏÎïÀÛ»ýÎȶ¨³£Êý¦Â4=10414£¬ºöÂÔ¦Â1£¬¦Â2£¬¦Â3£¬log¦ÁY(H)=0.45£© A.7.1¡Á10-11 B.7.1¡Á10-12 C.7.1¡Á10-10 D.7.1¡Á10-16 E.7.1¡Á10-13 7£® ΢ÈÜ»¯ºÏÎïCaF2ÔÚpH=3.00µÄË®½éÖÊÖеÄÈܽâΪ£º£¨CaF2µÄKsp=2.7¡Á10-11,HFµÄ
Ka=6.6¡Á10-4£©C A.1.40¡Á10-3mol¡¤L-1 B.6.96¡Á10-4mol¡¤L-1 C.3.48¡Á10-4mol¡¤L-1 D.1.74¡Á10-4mol¡¤L-1 E.3.48¡Á10-5mol¡¤L-1
1£®ÒÑÖªÁÚ±½¶þ¼×ËáÇâ¼Ø£¨KHC8H4O4£©Ä¦¶ûÖÊÁ¿Îª204.2g/mol£¬ÓÃËüÀ´±ê¶¨0.1mol¡¤L-1NaOHÈÜ
13
Òº£¬Ó¦³ÆÈ¡ÁÚ±½¶þ¼×ËáÇâ¼ØµÄÖÊÁ¿Îª£¨E £©
A£®0.25g×óÓÒ B.1g×óÓÒ C.0.1g×óÓÒ D.0.05g×óÓÒ E.0.5g×óÓÒ 2£®ÏÂÁÐÓйئÁY£¨H£©µÄÕýȷ˵·¨ÊÇ£¨C £©
A£® ¦ÁY£¨H£©ÊÇEDTAµÄ¸±·´Ó¦ÏµÊý£¬Ëü·´Ó³ÁËEDTA·¢Éú¸±·´Ó¦µÄ³Ì¶È¡£ B£® ¦ÁY£¨H£©ÊÇEDTAÖеÄY4- ·Ö²¼ÏµÊý¡£
C£® ¦ÁY£¨H£©ÊÇËáЧӦϵÊý£¬ËæpHÖµÔö´ó¶ø¼õС¡£ D£® ÔÚpHÖµ½ÏСµÄÈÜÒºÖУ¬EDTAµÄ¦ÁY£¨H£©Ô¼ÎªÁã¡£
E£® ÒÔÉÏ˵·¨¾ù²»ÕýÈ·¡£
3.ijѧÉú²â¶¨¿óʯÖÐ͵İٷֺ¬Á¿Ê±£¬µÃµ½ÏÂÁнá¹û£º2.50,2.53£¬2.55£¬ÓÃ4d·¨Ôò¹À¼ÆÔٲⶨһ´ÎËùµÃ·ÖÎö½á¹û²»Ó¦ÆúÈ¥µÄ½çÏÞÊÇ£¨E £©
A£®2.51-2.55 B.2.53?0.017 C.2.53?0.02 D.2.463-2.597 E.2.53?0.07 4£®ÓÃEDTAµÎ¶¨½ðÊô¸ÆÀë×Ó£¬ÒÑÖªlgKCaY=10.69,ÊÔ¹À¼ÆµÎ¶¨Ca2+µÄ×î¸ßÔÊÐíËá¶È´óԼΪpHÖµ£¨D £©
A£®2 B.4 C.6 D.8 E.10 5.³ÆÈ¡Ò»ÔªÈõËáHA 1.04g,׼ȷÅäÖÆ³É100.0ml,²âµÃpHֵΪ2.64£¬¼ÆËã¸ÃÒ»ÔªÈõËápKaµÄ½üËÆÖµ¡££¨HAµÄ·Ö×ÓÁ¿Îª122.1£©C
A£®2.10 B.6.20 C.4.20 D.3.40 E.5.20
6£®ÒÑÖªÔÚ0.10 mol?L-1Ag(NH3)2+ÈÜÒºÖУ¬º¬ÓÐÓÎÀëNH3µÄŨ¶ÈΪ0.10 mol?L-1£¬¼ÆËãÈÜÒºÖÐÓÎÀëAg+µÄŨ¶È¡££¨Ag+-NH3ÂçºÏÎïµÄÀÛ»ýÎȶ¨³£Êý¦Â1=1.7¡Á103£¬¦Â2=1.0¡Á107£©£¨B £© A£®1.0¡Á10-mol?L-1 B.1.0¡Á10mol?L-1 C.1.0¡Á10-mol?L-1 D. 1.0¡Á10-mol?L-1 E.1.0¡Á10-mol?L-1
7.¼ÆËãÒÔKBrO3µÎ¶¨Br-ÕâÒ»µÎ¶¨·´Ó¦µÄƽºâ³£Êý£¨A £©
BrO3-+5Br-+6H+¨T3Br2+3H2O (¦ÕBrO3-/Br2¨T1.52V, ¦ÕBr2/Br-¨T1.09V) A.2.8¡Á10
36
¦È
¦È
8-67
910
B.7.6¡Á10 C.3.7¡Á10 D.1.7¡Á10 E.4.2¡Á10
72144453
.8.΢ÈÜ»¯ºÏÎï
AgIÔÚË®ÖеÄÈܽâ¶ÈÊÇ500mlÖÐΪ1.40¦Ìg, AgIµÄʽÁ¿Îª234.80£¬Î¢ÈÜ»¯ºÏÎïµÄÈܶȻýΪ£º£¨E £© A£®1.2¡Á10 B.1.2¡Á10
-8
-10
C.1.2¡Á10 D.1.4¡Á10 E.1.4¡Á10
-12
-14-16
14
1¡¢·ÖÎö»¯Ñ§ÒÀ¾Ý·ÖÎöµÄÄ¿µÄ¡¢ÈÎÎñ¿É·ÖΪ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
£¨ A £©
A£º¶¨ÐÔ·ÖÎö¡¢¶¨Á¿·ÖÎö¡¢½á¹¹·ÖÎö B£º³£Á¿·ÖÎö¡¢°ë΢Á¿·ÖÎö¡¢Î¢Á¿·ÖÎö
C£ºÎÞ»ú·ÖÎö¡¢Óлú·ÖÎö D£º»¯Ñ§·ÖÎö¡¢ÒÇÆ÷·ÖÎö
2¡¢ÏÂÁÐÎó²îÊôÓÚϵͳÎó²îµÄÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
£¨ B £©
A£ºÌìÆ½ÁãµãͻȻ±ä»¯ B£º¶ÁÈ¡µÎ¶¨¹ÜµÄ¶ÈÊýÁ¿Æ«¸ß C£º»·¾³Î¶ȷ¢Éú±ä»¯ D£º»·¾³Êª¶È·¢Éú±ä»¯
3¡¢ÓÃÓÚ·´Ó¦ËÙ¶ÈÂý»ò·´Ó¦ÎïÊǹÌÌ壬¼ÓÈëµÎ¶¨¼Áºó²»ÄÜÁ¢¼´¶¨Á¿Íê³É»òûÓÐÊʵ±µÄָʾ¼ÁµÄµÎ¶¨·´Ó¦£¬³£²ÉÓõĵζ¨·½·¨
ÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨ B £© A£ºÖ±½ÓµÎ¶¨·¨ B£º·µµÎ¶¨·¨
C£ºÖû»µÎ¶¨·¨ D£º¼ä½ÓµÎ¶¨·¨
4¡¢ÒÔÏÂÊÔ¼Á²»ÄÜ×÷Ϊ»ù×¼ÎïÖʵÄÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨ D £©
A£ºÓż¶´¿µÄNa2B4O7¡¤10H2O B£º99.99£¥µÄ´¿Ð¿ C£º105-110¡£Cºæ¸É2hµÄNa2C2O4 D£ººæ¸ÉµÄNa2C03
5¡¢Ä³AgNO3±ê×¼ÈÜÒºµÄµÎ¶¨¶ÈΪTAgNO3/NaCl=0.005858g/L£¬ÈôM NaCl=58.44£¬Ôò
AgNO3±ê×¼ÈÜÒºµÄŨ¶È
ÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨ B £©
A£º1.0 mol.L-1 B£º0.1002 mol.L-1 C£º0.0100 mol.L-1 D£º0.1 mol.L-1
6¡¢ÏÂÁи÷×é»ìºÏÒºÖУ¬¿É×÷Ϊ»º³åÈÜҺʹÓõÄÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡¡
£¨ C £©
A£º0.1mol.L-1HClÓë0.05mol.L-1NaOHµÈÌå»ý»ìºÏ B£º0.1mol.L-1HAc0.1mLÓë0.1mol.L-1NaAc1LÏà»ìºÏ C£º0.2mol.L-1NaHC03Óë0.1mol.l-1NaOHµÈÌå»ý»ìºÏ D£º0.1mol.L-1NH3¡¤H20lmLÓë0.1mol.L-1NH4CllmL¼°1LË®Ïà»ìºÏ
7¡¢ÔÚEDTAÖ±½ÓµÎ¶¨·¨ÖУ¬ÖÕµãËù³ÊÏÖµÄÑÕÉ«ÊÇ£º¡¡¡¡¡¡¡¡¡¡¡¡
£¨ B £©
A: ½ðÊôָʾ¼ÁÓë´ý²â½ðÊôÀë×ÓÐγɵÄÅäºÏÎïµÄÑÕÉ«
15