»¯¹¤Ô­Àí¿Î³ÌÉè¼Æ(ÄÌ·ÛÅçÎí¸ÉÔï) ÏÂÔØ±¾ÎÄ

G1 tM1=55¡æ ÐÂÏÊ¿ÕÆø ÕôÆû ÈÈ¿ÕÆø ŨÄÌ ÅÅÆø L t0§æ0 H0¦ÔH0 I0 L t1 H1¦ÔH1 I1 L t2 H2¦ÔH2 I2 §æ2 t0=20¡æ£¬§æ0=50% t1=150¡æ,H1=0.00726 t2=80¡æ£¬H2=0.0339 H0=0.00726 ÈÈËðʧQL ¿ÕÆø¼ÓÈÈÆ÷ ÀäÄýË® ¸ÉÔïËþ ÄÌ·ÛG2 tM2=70¡æ

ͼ2ÎïÁÏ¡¢ÈÈÁ¿ºâËãͼ

2.1.1.1ÐÂÏÊ¿ÕÆø×´Ì¬²ÎÊý

ÓÉÉè¼ÆÈÎÎñÊ鏸¶¨Ìõ¼þ£ºt0£½20¡æ,§æ0£½50%

²éµÃ20¡æ±¥ºÍË®ÕôÆûѹPs0£½17.54 mmHg (2338.59Pa) ʪ¶ÈH0=0.622§æ0Ps0/(P-§æ0Ps0)

=0.622*0.5*17.54/(760-0.5*17.54) =0.00726kgË®/kg¾ø¸ÉÆø ÈÈìÊI0=(1.01+1.88H0) t0+2490H0

=(1.01+1.88*0.00726)*20+2490*0.00726 =38.554kJ/kg¾ø¸ÉÆø

ʪ±ÈÈݦÔH0=(1/29+H/18)*22.4*(273+t0)/273

=(1/29+0.00726/18)*22.4*(273+ 20)/273 =0.8387m3(ʪ¿ÕÆø)/kg¾ø¸ÉÆø

2.1.1.2¼ÓÈȺó¿ÕÆøµÄ״̬²ÎÊý£º£¨[2]£¬P467¡£[7],P229-P233£©

ȫ֬Èé·ÛµÄ¼Ó¹¤¹¤ÒÕÁ÷³ÌÖУ¬ÅçÎí¸ÉÔïµÄ²Ù×÷ÒªµãΪÏȽ«¹ýÂËµÄ¿ÕÆøÓɹķç»úÎü½ø£¬Í¨¹ý¿ÕÆø¼ÓÈÈÆ÷¼ÓÈÈÖÁ130-160¡æºó£¬ËÍÈëÅçÎí¸ÉÔïÊÒ¡£ÈçÓõçÈÈ»òȼÓͯ¼ÓÈÈ£¬¿Éʹ¸ÉÔï½éÖʵÄζÈÌá¸ßÖÁ200¡æÒÔÉÏ¡£ËäÈ»Ìá¸ßÈÈ¿ÕÆøÎ¶ȿÉÒÔÌá¸ßÈÈЧÂÊ£¬Ç¿»¯¸ÉÔï¹ý³Ì£¬¼õÉÙ¸ÉÔïËþËùÐèÈÝ»ý£¬µ«ÊÇ¿¼Âǵ½Î¶ȹý¸ß»áÓ°ÏìÈé·ÛµÄÖÊÁ¿£¬Èç·¢Éú¹êÁÑ»ò½¹»¯£¬ËùÒÔ¸ÉÔï½éÖʵÄζȻáÊܵ½ÏÞÖÆ¡£Í¬Ê±Î¶ȹýµÍ»áʹ²úÆ·Ë®·Öº¬Á¿¹ý¸ß¶ø²»ÄÜ´ïµ½±ê×¼¡£¹Ê¼ÓÈȺóµÄ¿ÕÆøÎ¶ȿÉÈ·¶¨Îª150¡æ¡£

ʪ¶ÈH1=H0=0.00726KgË®/Kg¾ø¸ÉÆø

ÈÈìÊI1=(1.01+1.88*H1)*t1+2490H1

=(1.01+1.88*0.00726)*150+2490*0.00726 =171.628KJ/Kg¾ø¸ÉÆø

ʪ±ÈÈݦÔH1£½(1/29+ H1/18)*22.4*(273+ t1)/273

=(1/29+0.00726/18)*22.4*(273+ 150)/273 =1.211m3(ʪ¿ÕÆø)/kg¾ø¸ÉÆø

2.1.1.3ÅÅ·ç״̬²ÎÊýÈ·¶¨£º£¨»ã±à,P1-8£¬[7],P305£©

¸ÉÔïµÄÈé·Ûº¬Ë®·Ö2.5%ÒÔÄÚ£¬´ÓËþµ×Á÷³ö£¬ÈÈ¿ÕÆø¾­Ðý·ç·ÖÀëÆ÷ÊÕ¼¯ËùЯ´øµÄÈé·Û¿ÅÁ££¬¾»»¯ºóµÄ¿ÕÆø±»ÅÅ·ç»úËÍÈë´óÆøÖУ¬ÅÅ·ÅζÈΪ80-90¡æ£¬Ïà¶Ôʪ¶ÈΪ10-12%¡£Ñ¡¶¨ÅÅ·ÅζÈΪ80¡æ¡£µ«ÎªÁË·ÀÖ¹²úÆ·³¤Ê±¼äÊܸßÎÂÓ°Ïì¶øÊ¹²úÆ·±äÐÔ£¬ÇÒͬʱҲҪ·Àֹ¶ˮµÄÐγɣ¬¹ÊÄÌ·Û³ö¿ÚζÈÒ»°ã±ÈÅÅÆøÎ¶ȵÍ10¡æ¡£ ¾ÍÕû¸ö¸ÉÔïÆ÷×÷ÈÈÁ¿ºâË㣬£¨[1]ϲá,P230£©

G2CMtM1/W + Cl tM1 +lI0 +l(I1-I0) = G2CM tM2 /W + lI2 +QL

ʽÖУºCM-----²úÆ·±ÈÈÈ£¬È«Ö¬ÄÌ·ÛΪ2.1kJ/kg¡æ (ÈÎÎñÊ鏸¶¨)

Cl-----Ë®µÄ±ÈÈÈ£¬4.187kJ/kg¾ø¸ÉÆø

tM1-----ŨÄÌζȣ¬ÈÎÎñÊ鏸¶¨55¡æ (ÈÎÎñÊ鏸¶¨) tM2-----ÄÌ·Û³ö¿Úζȣ¬È¡70¡æ

QL-----ÿÕô·¢1kgË®¸ÉÔïÊÒµÄÈÈËðʧ£¬°´¹¤ÒµÉú²ú¾­ÑéÈ¡251kJ/kgË®£¨[7],P305£º¶ÔÓÚ±£ÎÂÊÊÒ˵ĸÉÔïÊÒ¶øÑÔ£ºÆäɢʧµÄÈÈÁ¿¿ÉÈ¡60ǧ¿¨/¹«½ïË®£¬Ï൱ÓÚ251.04kJ/kgË®£¬¶ø¶ÔÓÚ¿ÕÆø¼ÓÈÈÆ÷µÄÈÈËðʧ¿ÉÈ¡40ǧ¿¨/¹«½ïË®£¬Ï൱ÓÚ167.36kJ/kgË®¡£±¾¹¤ÒÕ±£ÎÂÊÊÒË£¬¹Ê²ÉÓÃÈÈËðʧΪ251kJ/kgË®¡££©

W-----ÿСʱÕô·¢Ë®Á¿£¨¼ûÎïÁϺâË㣩221.77kg G2-----ÿСʱÄÌ·Û²úÁ¿ £¨¼ûÎïÁϺâË㣩215.05kg l-----ÿÕô·¢£±Ç§¿ËË®ËùÐè¿ÕÆøÁ¿Kg,l£½1/(H2£­H1) ½«ÉÏʽÕûÀíºó¿ÉµÃ£º

Cl tM1-(G2CM tM2 /W£­G2CMtM1/W+QL)=(I2-I1)/(H2-H1)

·½³Ì×ó¶Ë±íʾ¸ÉÔïÊÒ²¹³äÈÈÁ¿ÓëËðʧÈÈÁ¿Ö®²î£¬Ó椱íʾ¡£ ¦¤=4.187*55-(215.05*2.1*70/221.77-215.05*2.1*55/221.77+251) =-51.2605KJ/KgË®

¦¤=(I2-I1)/(H2£­H1)

=[(1.01+1.88H2)t2+2490H2-I1]/(H2£­H1) =[(1.01+1.88H2)*80+2490H2-171.628)/(H2-0.00726) =-51.2605KJ/KgË®

½âµÃ:H2£½0.03388 KgË®/Kg¾ø¸ÉÆø ÈÈìÊI2£½(1.01+1.88 H2)t2+2490 H2

£½(1.01+1.88*0.03388)*80+2490*0.03388 £½170.25675kJ/kg¾ø¸ÉÆø

§æ2µÄÇóÈ¡£ºÓÉH2£½0.622§æ2PS2/(P-§æ2PS2) ²éµÃ80¡æ±¥ºÍË®ÕôÆûѹPS2£½355.1mmHg

0.03388£½0.622*355.1§æ2/(760-355.1*§æ2)

½âµÃ£º§æ2£½11.06%©‚12%

Ϊ±£Ö¤Èé·ÛË®·Öº¬Á¿µÄÒªÇ󣬱ØÐëÑϸñ¿ØÖÆÅÅ·çÏà¶Ôʪ¶È§æ2=10¡«12%¡£ÓÉÓÚ§æ2ÔÚ´Ë·¶Î§ÒÔÄÚ£¬ËùÒÔº¬Ë®Á¿¿ÉÒÔ±£Ö¤¡£ ʪ±ÈÈݦÔH2=(1/29+H/18)*22.4*(273+t2)/273

=(1/29+0.03388/18)*22.4*(273+80)/273 =1.0533m3(ʪ¿ÕÆø)/kg¾ø¸ÉÆø

2.1.2ÎïÁϺâË㣺

2.1.2.1 ÿСʱÐèµÃÄÌ·ÛÁ¿G2¿ÉÓÉÄê²úÁ¿£¬Ä깤×÷ÈÕ£¬ÈÕ¹¤×÷°àÊý¼°ÅçÎíʱ¼äÇóÈ¡£¨Ïà¹ØÊý¾ÝÓÉÈÎÎñÊ鏸¶¨£ºÄê²úȫ֬ÄÌ·Û800¶Ö£¬Ä깤×÷ÈÕΪ310Ì죬ÈÕ¹¤×÷¶þ°à£¬°àʵ¼ÊÅçÎíʱ¼ä6Сʱ£©

G2=800*1000/(310*2*6)=215.05kg/h 2.1.2.2 ÿСʱÅçÎíŨÄÌÁ¿¼°Õô·¢Ë®·ÖÁ¿W G1=G2*(1-W2)/(1-W1) =215.05*(1-0.025)/(1-0.52) =436.82Kg/h

W=G1-G2=436.82-215.05=221.77kg/h

2.1.2.3ÿÕô·¢1kgË®¸É¿ÕÆøÓÃÁ¿£¨¾ø¸ÉÁ¿¼Æ£©

L=1/(H2£­H1)£½1/(0.03388-0.00726£© =37.566kg¾ø¸ÉÆø/kgË® ÿСʱ¸É¿ÕÆøÁ¿

L£½W/(H2£­H1)£½221.77/£¨0.03388-0.00726£©=8330.9542Kg¾ø¸ÉÆø/h ÐÂÏÊ¿ÕÆøÌå»ýÁ÷Á¿

V0=L¦ÔH0=8330.9542*0.8387=6987.1713m3/h ÈÈ¿ÕÆøÌå»ýÁ÷Á¿

V1=L¦ÔH1=8330.9542*1.211=10088.785m3/h ÅÅÆøÌå»ýÁ÷Á¿

V2=L¦ÔH2£½8330.9542*1.0533=8774.994m3/h

2.1.3ÈÈÁ¿ºâËã 2.1.3.1 ÊäÈëϵͳÈÈÁ¿

ÐÂÏÊ¿ÕÆøÊäÈë:Q1=LI0=8330.9542*38.554=321191.61kJ/h

¼ÓÈÈÆ÷ÊäÈëÈÈÁ¿£ºQ2=L(I1- I0)£½8330.9542*(171.628 -38.554)=1108633.4 kJ/h ŨÄÌ´øÈëµÄÈÈÁ¿£ºQ3=G2CMtM1+WCl tM1£½215.05*2.1*55+221.77*4.187*55

=75908.579KJ/h

¦²QÈë=Q1+ Q2+ Q3=321191.61+1108633.4+75908.579=1505733.6kJ/h

2.1.3.2 Êä³öϵͳµÄÈÈÁ¿

ÅÅÆø´ø³öµÄÈÈÁ¿:Q¡¯1=LI2 =8330.9542*170.25675 =1418401.2KJ/h ²úÆ·ÄÌ·Û´ø³öµÄÈÈÁ¿£ºQ¡¯2£½G2CMtM2£½215.05*2.1*70=31612.35KJ/h ¸ÉÔïÊÒÈÈËðʧ£ºQ¡¯3= WQL£½221.77*251=55664.27KJ/h

¦²Q³ö£½Q¡¯1+ Q¡¯2+ Q¡¯3= 1418401.2+31612.35+55664.27=1505677.8 KJ/h

ÓÉÓÚ¦²Q³ö£½¦²QÈ룬¿É¼ûÈÈÁ¿ÊÕ֧ƽºâ¡£

2.1.3.3 ¸ÉÔï¹ý³ÌµÄÈÈЧÂÊ£º±íʾÿÕô·¢1kgË®·Ö£¬¸ÉÔïÆ÷ÄÚËùÐè¼ÓÈëµÄÈÈÁ¿ÖÐÓÃÓÚÆû»¯Ë®·ÖËùºÄÈÈÁ¿µÄ°Ù·ÖÂÊ¡£ ¦Ç=((r0+CWt2)-CltM1)/l(I2£­I0)

=((2490+1.88*80)-4.187*55)/37.566(170.25675-38.554)=48.7%

2.1.3.4 ¿ÕÆø¼ÓÈÈÆ÷ÕôÆûÏûºÄÁ¿£º£¨[5],P266£© ѡȡ¼ÓÈÈÓñ¥ºÍË®ÕôÆøÎ¶ÈT= t1+10=150+10=160¡æ

²éµÃÆä±¥ºÍÕôÆûѹΪ6.303Kgf/cm2(¾øÑ¹)£¬Æû»¯Ç±ÈÈΪ2087.1kJ/kg ²¢È¡ÈÈЧÂʦÇk=95%

ÕôÆûÏûºÄÁ¿:Dk=Q2/r¦Çk=1108633.4/2087.1*0.95=504.62kg/h

2.2ÀëÐÄʽÎí»¯Æ÷µÄ¼ÆË㣺

¸ù¾ÝÏÖÓе͍ÐÍÉ豸LP150£¬ÓÃÆäÓйØÊý¾Ý½øÐвο¼Éè¼Æ¡£

G1=436.82kg/h ¦Ñ=1120kg/m3

436.82?103??390.02L/h V1=?11120G1¹Ê¿ÉѡȡÉú²úÄÜÁ¦Îª400L/hµÄÀëÐÄÎí»¯Æ÷¡£

ҪʹÅç¿×Á÷ËÙU¿×ÔÚ0.5~1m/sÖ®¼ä£¬¿ÉÔö´ó¿×¾¶ÖÁ5mm£¬²ÉÓÃ6¸öÅç¿×¡£

ºËËãU¿×?390.02?103?4?0.9196ms

?5?6?36002U¿×ÔÚ0.5~1m/s¼ä£¬ÊÊÓÃÑ¡LP400

LP400£º²ÎÊýÈçÏ£º Éú²úÄÜÁ¦£º400L/h

Ö÷ÒªÐÔÄܲÎÊý£ºÀëÐÄÅÌÅç×ìÍâ¾¶£º280mm

Åç×ì¸öÊý£º 6¸ö Åç×ì¿×¾¶£º 5mm ÀëÐÄÅÌתËÙ£º 7300r/mim ÀëÐÄÅÌÏßËÙ¶È£º 104m/s

ÉÏÊö²ÉÓòο¼ÐÔÉè¼Æ£¬ÓÉÓÚÀëÐÄÎí»¯Æ÷½á¹¹Ïà¶Ô½Ï¸´ÔÓ£¬¹Ê²»ÖØÐ½øÐÐÉè¼Æ£¬µ«¿ÉÓÃÏÖÓÐÐͺŵÄÎí»¯Æ÷£¬²¢¶ÔÉú²úÄÜÁ¦·½ÃæµÄ²ÎÊý×ö΢µ÷¡£±¾´ÎÉè¼ÆÍ¨¹ýÀ©´óÅç×ì¿Ú¾¶ºÍÔö¼ÓÅç¿ÚÊýÁ¿Ê¹Åç×ìµÄÒºÌåÁ÷ËÙ¿ØÖÆÔÚ0.5~1m/sÄÚ£¬ËæºóÔÙ¶ÔÅç×ìµÄÐÔÄܲÎÊý×öÏàÓ¦µÄµ÷Õû£¬×îºóÁгöÖ÷ÒªÐÔÄܲÎÊý¡£

2.2.1ÎíµÎÖ±¾¶dLµÄ¼ÆËã([6]£¬P432)

ÔÚºöÂÔÁË·ÖÉ¢ÅÌÐÎ×´¶ÔÎíµÎµÄÓ°Ïìʱ£¬ÓÐÈËÌá³öÏÂÃæµÄ¶à¹Üʽ·ÖÉ¢ÅÌÎíµÎÖ±