热力发电厂试题-1 下载本文

.

D′0=3600×6000/(957.44×0.95)=23747.54kg/h d′0= D′0/ Pe=23747.54/6000=3.958kg/(kWh)

q′0= d′0(h0-h′c)=3.958×(3305-121.4)=12600.69kJ/(kWh) η′e=3600/ q′0=3600/12600.69=0.286 η′cp=ηbηpη′e=0.90×0.98×0.286=0.252

δη=(η′cp-ηcp)/ηcp=(0.252-0.247)/0.247×100%=2.02%

精选范本