middle=scro(1,chb1+1:chb2);

scro(1,chb1+1:chb2)=scro(2,chb1+1:chb2); scro(2,chb1+1:chb2)=middle; for i=1:chb1

while find(scro(1,chb1+1:chb2)==scro(1,i)) zhi=find(scro(1,chb1+1:chb2)==scro(1,i)); y=scro(2,chb1+zhi); scro(1,i)=y; end

while find(scro(2,chb1+1:chb2)==scro(2,i)) zhi=find(scro(2,chb1+1:chb2)==scro(2,i)); y=scro(1,chb1+zhi); scro(2,i)=y; end end

for i=chb2+1:bn

while find(scro(1,1:chb2)==scro(1,i)) zhi=find(scro(1,1:chb2)==scro(1,i)); y=scro(2,zhi); scro(1,i)=y; end

while find(scro(2,1:chb2)==scro(2,i))

zhi=find(scro(2,1:chb2)==scro(2,i)); y=scro(1,zhi); scro(2,i)=y; end end end end

%-------------------------------------------------- %“变异”操作

function snnew=mut(snew,pm);

bn=size(snew,2); snnew=snew;

pmm=pro(pm); %根据变异概率决定是否进行变异操作，1则是，0则否 if pmm==1

c1=round(rand*(bn-2))+1; %在[1,bn-1]范围内随机产生一个变异位

c2=round(rand*(bn-2))+1; chb1=min(c1,c2);

chb2=max(c1,c2); x=snew(chb1+1:chb2); snnew(chb1+1:chb2)=fliplr(x); end End

六、实验结果：

运行状态：