(5) ÖÐÐÄÔ×ÓP²ÉÈ¡²»µÈÐÔsp3ÔÓ»¯,Èý½Ç×¶£¬¦Ì¡Ù0£¬¼«ÐÔ·Ö×Ó
17. ˵Ã÷ÏÂÁÐÿ×é·Ö×Ӽ䴿ÔÚ×ÅʲôÐÎʽµÄ·Ö×Ó¼ä×÷ÓÃÁ¦£¨È¡ÏòÁ¦¡¢ÓÕµ¼Á¦¡¢É«É¢Á¦¡¢Çâ¼ü£©¡£
£¨1£©±½ºÍCCl4£¨É«É¢Á¦£© £¨2£©¼×´¼ºÍË®£¨È¡ÏòÁ¦¡¢ÓÕµ¼Á¦¡¢É«É¢Á¦¡¢Çâ¼ü£© £¨3£©HBrÆøÌ壨ȡÏòÁ¦¡¢ÓÕµ¼Á¦¡¢É«É¢Á¦£© £¨4£©HeºÍË®£¨ÓÕµ¼Á¦¡¢É«É¢Á¦£© £¨5£©HClºÍË®£¨È¡ÏòÁ¦¡¢ÓÕµ¼Á¦¡¢É«É¢Á¦£©
18. ÒÒ´¼ºÍ¼×ÃÑ£¨CH3OCH3£©ÊÇͬ·ÖÒì¹¹Ì壬µ«Ç°Õ߷еãΪ78.5¡æ£¬ºóÕߵķеãΪ-23¡æ¡£ÊÔ½âÊÍÖ®¡£ÒÒ´¼ÓÐÇâ¼ü£¬¶ø¼×ÃÑûÓÐ
19. ÏÂÁи÷ÎïÖÊÖÐÄÄЩ¿ÉÈÜÓÚË®£¿ÄÄЩÄÑÈÜÓÚË®£¿ÊÔ¸ù¾Ý·Ö×ӵĽṹ¼òµ¥ËµÃ÷Ö®¡£ £¨1£©¼×´¼ £¨2£©±ûͪ £¨3£©ÂÈ·Â £¨4£©ÒÒÃÑ £¨5£©¼×È© £¨6£©¼×Íé 20. ÔÚHe+Àë×ÓÖÐ,3s¡¢3p¡¢3d¡¢4s¹ìµÀÄܼ¶×ÔµÍÖÁ¸ßÅÅÁÐ˳ÐòΪ_3s=3p=3d£¼4s__£¬ÔÚKÔ×ÓÖУ¬Ë³ÐòΪ_3s£¼3p£¼4s£¼3d£¬MnÔ×ÓÖÐ,˳ÐòΪ_3s£¼3p£¼4s£¼3d¡£
21. AÔ×ÓµÄM²ã±ÈBÔ×ÓµÄM²ãÉÙ4¸öµç×Ó£¬BÔ×ÓµÄN²ã±ÈAÔ×ÓµÄN²ã¶à5¸ö µç×Ó£¬ÔòA¡¢BµÄÔªËØ·ûºÅ·Ö±ðΪ Fe ¡¢ Br £¬AÓëBµÄµ¥ÖÊÔÚËáÐÔÈÜÒºÖз´Ó¦µÃµ½µÄÁ½ÖÖ»¯ºÏÎï·Ö±ðΪ FeBr2 ¡¢ FeBr3 ¡£
22.Ä³ÔªËØ»ù̬Ô×Ó£¬ÓÐÁ¿×ÓÊýn=4£¬l=0£¬m=0µÄÒ»¸öµç×ÓºÍn=3£¬l=2µÄ10¸öµç×Ó£¬¸ÃÔªËØµÄ¼Ûµç×ӽṹÊÇ 3d104s1 £¬Î»ÓÚÔªËØÖÜÆÚ±íµÚ 4 ÖÜÆÚ£¬µÚ ¢ñB ×å¡£
23.µÚÎåÖÜÆÚÄ³ÔªËØ,ÆäÔ×Óʧȥ2¸öµç×Ó,ÔÚl = 2µÄ¹ìµÀÄÚµç×ÓÈ«³äÂú,£¬ÊÔÍÆ¶Ï¸Ã ÔªËØµÄÔ×ÓÐòÊý¡¢µç×ӽṹ£¬²¢Ö¸³öλÓÚÖÜÆÚ±íÖÐÄÇÒ»×壿ÊÇÊ²Ã´ÔªËØ£¿ 48£¬[Kr]4d105s2,µÚÎåÖÜÆÚ£¬µÚ¢òB×壬ïÓ£¬Cd
24. ÊÔÅжÏÏÂÁи÷×黯ºÏÎïÈÛµã¸ßµÍ˳Ðò£¬²¢¼òµ¥½âÊÍÖ®¡£ £¨1£©NaF £¾ NaCl £¾ NaBr £¾ NaI £¨2£©SiF4 £¼ SiC14 £¼ SiBr4 £¼ SiI4
25. ÁÚÏõ»ù±½·ÓµÄÈÛ¡¢·Ðµã±È¶ÔÏõ»ù±½·ÓµÄÈÛ¡¢·ÐµãÒª_µÍ_ÕâÊÇÒòΪÁÚÏõ»ù±½·Ó´æÔÚ ·Ö×ÓÄÚÇâ¼ü£¬¶ø¶ÔÏõ»ù±½·Ó´æÔÚ·Ö×Ó¼äÇâ¼ü£¬ÕâÁ½ÖÖÒì¹¹ÌåÖУ¬¶ÔÏõ»ù±½·Ó½ÏÒ×ÈÜÓÚË®¡£ 26. Ï¡ÓÐÆøÌåºÍ½ð¸Õʯ¾§¸ñ¸ñµãÉ϶¼ÊÇÔ×Ó£¬µ«ÎªÊ²Ã´ËüÃǵÄÎïÀíÐÔÖÊÏà²îÉõÔ¶£¿ Ï¡ÓÐÆøÌå·Ö×Ó¾§Ì壬½ð¸Õʯ¾§ÊÇÔ×Ó¾§Ìå¡£
µÚÁùÕ Ëá¼îƽºâ¼°Ëá¼îµÎ¶¨
6-1.Ëá¼îÖÊ×ÓÀíÂÛÊÇÈçºÎ¶¨ÒåËáºÍ¼îµÄ£¿Ê²Ã´½Ð¹²éîËá¼î¶Ô£¿ 6-2.ÏÂÁÐ˵·¨ÊÇ·ñÕýÈ·£¬Èô²»ÕýÈ·ÇëÓèÒÔ¸üÕý¡£
£¨1£©¸ù¾ÝÏ¡ÊͶ¨ÂÉ£¬ÈõËáµÄŨ¶ÈÔ½´óÆä½âÀë¶ÈԽС£¬Òò´ËÆäËá¶ÈҲԽС¡£´í
£¨2£©ÒòΪÖкÍÏàͬŨ¶ÈºÍÌå»ýµÄÑÎËáºÍ´×ËáËùÐè¼îµÄÁ¿ÏàµÈ£¬ËùÒÔËüÃǵÄÈÜÒºÖÐH+Àë×ÓŨ¶ÈÒ²Ïàͬ¡£´í
£
£¨3£©ÓÃHCl±ê×¼ÈÜÒºµÎ¶¨NaOH£¨Å¨¶È¾ùΪ0.1mol?L1£©£¬ÒÔ¼×»ùºìΪָʾ¼Áʱ£¬ÖÕµãÎó ²îΪ¸ºÎó²î¡£´í
££
£¨4£©20mL0.1 mol¡¤L1µÄHCOOHÓë10mL0.1mol¡¤L1µÄNaOHÏà»ìºÏ£¬Æä»ìºÏÈÜÒºÊÇ»º³åÈÜÒº¡£ÕýÈ·
6-3. д³öÏÂÁи÷ËáµÄ¹²éî¼î£ºH2O- OH-£¬H2C2O4-H2C2O4-£¬HCO3-- CO32-£¬H2PO4--HPO42-£¬HS--S2-£¬C6H5NH3+-C6H5NH2¡£
6-4. д³öÏÂÁи÷¼îµÄ¹²éîË᣺H2O-H3O+£¬HC2O4--H2C2O4£¬HCO3--H2CO3£¬H2PO4--H3PO4£¬HS--H2S£¬S2--HS-¡£
6-5. ÍùHAcµÄÏ¡ÈÜÒºÖзֱð¼ÓÈëÉÙÁ¿£¨1£©HCl£»£¨2£©NaAc£»£¨3£©NaCl£»£¨4£©H2O£»£¨5£©NaOH£¬ÔòHAcµÄ½âÀë¶ÈÓкα仯£¿ÎªÊ²Ã´£¿
6-6£® ÓÃ0.1mol¡¤L-1µÄNaOHµÎ¶¨ÓÐ0.1mol¡¤L-1 NH4Cl´æÔÚµÄ0.1mol¡¤L-1HCl£¬ÖÕµãӦѡºÎÖÖָʾ¼Á£¿ÎªÊ²Ã´£¿¼×»ùºì
6-7. д³öÏÂÁÐÎïÖÊË®ÈÜÒºµÄÖÊ×ÓÌõ¼þʽ£º
£¨1£©NaAc £¨2£©HCl £¨3£©NaOH £¨4£©NH4Ac £¨5£©NaNH4HPO4 £¨6£©NH4H2PO4 (1) c(H+)+c(HAc)=c(OH-) (2) c(H+)=c(Cl-) +c(OH-) (3) c(OH-)=c(Na+) + c(H+)
(4) c(H+)+c(HAc)=c(OH-)+c(NH3) (5) c(H+)+c(H2PO4-)+2 c(H3PO4)=c(OH-)+c(NH3) +c(PO43-) (6) c(H+)+ c(H3PO4)=c(OH-)+c(NH3) +c(HPO42-)+2c(PO43-)
6-8£®Ñ¡ÔñÌâ
£¨1£©ÏÂÁÐÎïÖʼȿÉ×÷ËáÓÖ¿É×÷¼îµÄÊÇ£¨ A £©¡£
(A) H2O (B) Ac- (C) H2CO3 (D) CO32- £¨2£©ÓûÅäÖÆpH=7.00µÄ»º³åÈÜÒº£¬Ó¦Ñ¡ÔñµÄ»º³å¶ÔÊÇ£¨ C £©¡£ (A) NH3¡ªNH4Cl (B) H3PO4¡ªNaH2PO4 (C) NaH2PO4¡ªNa2HPO4 (D) Na2HPO4¡ªNa3PO4 £¨3£©ÏÂÁÐË®ÈÜÒºpH×îСµÄÊÇ£¨ C £©¡£
(A) NaHCO3 (B) Na2CO3 (C) NH4Cl (D) NH4Ac
£¨4£©µ±H3PO4ÈÜÒºµÄpH=3.00ʱ£¬ÈÜÒºÖÐÖ÷Òª´æÔÚµÄÐÍÌåΪ£¨ B £©¡£ (A) H3PO4 (B) H2PO4- (C) HPO42- (D) PO43-
(5) ÓÃÇ¿ËáµÎ¶¨Èõ¼îʱ£¬Í»Ô¾·¶Î§ÓëÈõ¼îµÄKb?µÄ¹ØÏµÊÇ£¨ C £©
£¨A£©Kb?Óú´ó£¬ÔòͻԾ·¶Î§ÓúÕ £¨B£©Kb?ÓúС£¬ÔòͻԾ·¶Î§Óú¿í £¨C£©Kb?Óú´ó£¬ÔòͻԾ·¶Î§Óú¿í £¨D£©Kb?ÓëͻԾµÄ´óСÎ޹ء£
£¨6£© ÓÃHClÈÜÒºµÎ¶¨Ä³¼îÑù£¬µÎÖÁ·Ó̪±äɫʱ£¬ÏûºÄÑÎËáV1 mL£¬ÔÙ¼ÓÈë¼×»ù³Èָʾ¼ÁÁ¬ÐøµÎ¶¨ÖÁ³ÈÉ«£¬ÓÖÏûºÄÑÎËáV2 mL£¬ÇÒV1>V2>£°£¬Ôò´Ë¼îÑùÊÇ£¨ D £©¡£
(A) NaOH (B) NaHCO3 + Na2CO3 (C) Na2CO3 (D) NaOH + Na2CO3
6-9.ÀûÓ÷ֲ¼ÏµÊý¼ÆËãpH=5.0ºÍpH=10.0ʱ0.1mol¡¤L-1NH4ClÈÜÒºÖи÷ÐÍÌåµÄƽºâŨ¶È¡£
10?55.6?10?10?5?1?(NH)??5.6?10½â£ºpH=5ʱ?(NH)??5 3?10?5?1010?5.6?1010?5.6?10?4c(NH4+)¡Ö0.1 mol¡¤L-1 c(NH3)¡Ö5.6310 mol¡¤L-1
-6
10?105.6?10?10?0.15?(NH3)??10?0.85 pH=10ʱ: ?(NH)??10?10?1010?5.6?1010?5.6?10?4c(NH4+)¡Ö0.015 mol¡¤L-1 c(NH3)¡Ö0.085 mol¡¤L-1
6-10£®ÈËÌåÖеÄCO2ÔÚѪҺÖÐÒÔHCO3-ºÍH2CO3´æÔÚ£¬ÈôѪҺµÄpHΪ7.4£¬ÇóѪҺÖÐHCO3-ºÍH2CO3¸÷Õ¼¶àÉٰٷÖÊý£¿
½â£º
(3.98?10?8)2?(H2CO3)??0.086 ?82?8?7?7?11(3.98?10)?3.98?10?4.2?10?4.2?10?5.6?103.98?10?8?4.2?10?7?(HCO)??0.91
(3.98?10?8)2?3.98?10?8?4.2?10?7?4.2?10?7?5.6?10?11-36-11. ÒÑÖªÏÂÁи÷ÖÖÈõËáµÄKaÖµ£¬ÇóËüÃǵĹ²éî¼îµÄKbÖµ£¬²¢½«¸÷¼î°´ÕÕ¼îÐÔÓÉÇ¿µ½ÈõµÄ˳Ðò½øÐÐÅÅÁС£
¦È¦È
(1) HCN Ka?=6.2¡Á1010£» (2) HCOOH Ka?=1.8¡Á104£»
££
(3) C6H5OH Ka?=1.1¡Á1010£» (4) H3BO3 Ka?=5.8¡Á1010 ½â£º
6-12£®¿ÕÆøÖеÄCO2ʹ½µË®ÓÐÒ»¶¨µÄËá¶È¡£¸ù¾Ý¸É¿ÕÆøÖÐCO2µÄº¬Á¿£¬¼ÆËãµÃµ½ÔÚÒ»¶¨Î¶ȺÍË®ÕôÆøÑ¹Ê±CO2ÔÚË®ÖеÄÈܽâ¶ÈΪ1.03¡Á10-5 mol¡¤L-1£¬Çó´Ë״̬ÏÂ×ÔÈ»½µË®µÄpHÖµ¡£
£
£
½â£ºc(H?)?1.03?10?5?4.2?10?7?2.08?10?6 mol¡¤L-1 pH=5.68
6-13£®ÇóÏÂÁÐÎïÖÊË®ÈÜÒºµÄpHÖµ£º £¨1£©0.01mol¡¤L-1HCl£» £¨2£©0.2mol¡¤L-1HAc£» £¨3£©0.5mol¡¤L-1NH3¡¤H2O£»
-1-1-1
£¨4£©0.05mol¡¤LNaAc£»£¨5£©0.1mol¡¤L (NH4)2SO4£» £¨6£©0.1mol¡¤L NaHCO3£» £¨7£©0.1mol¡¤L-1 Na2CO3£»£¨8£©0.1mol¡¤L-1 NaH2PO4£» £¨9£©0.04mol¡¤L-1 H2CO3£»
-3
½â£º(1) pH=2 (2) c(H+)=1.9310 mol¡¤L-1 pH=2.72 (3) pOH=2.52 pH=11.48 (4) pH=7.72 (5) pH=4.98 (6) pH=(6.38+10.25)/2=8.31 (7) pH=11.62 (8) Ka2c£¾20Kw c£¼20ka1, c(H)??Ka¦È1Ka¦È2(c¦È)2cKa¦È1c¦È?c7.6?10?3?6.3?10?8?0.1-1?5 mol¡¤L ??2.1?10?37.6?10?0.1pH=4.68 ÈôpH=(pKa1+pKa2)/2=(2.12+7.2)/2=4.66 (9) pH=3.89
6-14£®ÊµÑé²âµÃ0.1mol¡¤L-1HAcÈÜÒºµÄpH=2.88£¬ÇóHAcµÄKa?¼°½âÀë¶È¦Á¡£ÈôÔÚ´ËÈÜÒºÖмÓÈëNaAc²¢Ê¹ÆäŨ¶È´ïµ½0.1mol¡¤L-1£¬ÈÜÒºµÄpHºÍ½âÀë¶È¦ÁÓÖΪ¶àÉÙ£¿Õâ˵Ã÷ʲôÎÊÌ⣿
½â£º
c2(H?)(1.35?10?3)2Ka???1.82?10?5c0.1c(H?)1.35?10?3???100%??100%?1.35%
c0.1pH?pKa?lgcb0.1?4.74?lg?4.74 ca0.1c(H?)1.82?10?5???100%??100%?0.018% ͬÀë×ÓЧӦ
c0.16-15. ʲô½Ð»º³åÈÜÒº£¿»º³åÈÜÒº¾ßÓÐÄÄÐ©ÌØÐÔ£¿ÅäÖÆ»º³åÈÜҺʱ£¬ÈçºÎÑ¡ÔñºÏÊʵĻº
³å¶Ô£¿
6-16. 0.1mol¡¤L-1ijһԪÈõËᣨHA£©ÈÜÒº50mLÓë20mL0.1mol¡¤L-1 NaOHÈÜÒº»ìºÏ£¬½«»ìºÏÈÜҺϡÊ͵½100mL£¬ÓÃËá¶È¼Æ²âµÃÈÜÒºµÄpH=5.25£¬ÇóHAµÄKa?¡£
½â£ºpH?pKa?lg2?pKa?0.18?5.25 Ka=3.72310-6 36-17. ÔÚѪҺÖУ¬H2CO3-HCO3-»º³åÒº¹¦ÄÜÖ®Ò»ÊÇ´Óϸ°û×éÖ¯ÖпìËÙ³ýÈ¥Ô˶¯Ö®ºóËù²úÉúµÄÈéËáHL(HLµÄKa?=8.4¡Á10-4)
(1) Çó·´Ó¦£ºHL+ HCO3-= H2CO3+L-µÄ±ê׼ƽºâ³£Êý¡£
(2) ÔÚÕý³£ÑªÒºÖУ¬c(H2CO3)=0.0014mol?L-1, c(HCO3-)=0.027mol?L-1£¬Èç¹ûѪҺÖнöº¬ÓÐH2CO3£¬HCO3-£¬ÄÜά³ÖÕý³£ÑªÒºµÄpHÖµÂð£¿
(3) ÇóÔÚ¼ÓÈë0.0050mol?L-1µÄHLÖ®ºóµÄpH¡£
c(H2CO3)c(L?)c(H?)Ka(HL)8.4?10?4½â£º(1)K?????2?103 -??7c(HL)c(HCO3)c(H)Ka1(H2CO3)4.2?100.027?6.38?1.28?7.66£¾7.45
0.00140.027?0.005?6.38?0.54?6.92 (3) pH?6.38?lg0.0014?0.005(2)pH?pKa1?lg6-18ÏÖÓÐ1.0LÓÉHFºÍF-×é³ÉµÄ»º³åÈÜÒº¡£ÊÔ¼ÆË㣺
£¨1£©µ±¸Ã»º³åÈÜÒºÖк¬ÓÐ0.10 molHFºÍ0.30molNaFʱ£¬ÆäpHֵΪ¶àÉÙ£¿
£¨2£©Íù£¨1£©»º³åÈÜÒºÖмÓÈë0.40gNaOH¹ÌÌ壬²¢Ê¹ÆäÍêÈ«Èܽ⣨ÉèÈܽâºóÈÜÒºµÄÌå»ý²»±ä£©£¬ÎʸÃÈÜÒºµÄpHֵΪ¶àÉÙ£¿
£¨3£©µ±»º³åÈÜÒºpH=6.5ʱ£¬HFÓëF-Ũ¶ÈµÄ±ÈֵΪ¶àÉÙ£¿´ËʱÈÜÒº»¹Óлº³åÄÜÁ¦Â𣿠½â£º(1) pH?3.18?lg(2)pH?3.18?lg0.3?3.66 0.10.31?3.72£¾ 0.09c(HF)c(HF)?4.8?10?4 (3) 6.5?3.18?lg --c(F)c(F)Óô×ËáµÄŨ¶ÈΪ1.0mol¡¤L
£1
6-19 ÓûÅäÖÆpH=5.00µÄ»º³åÈÜÒº500mL£¬ÇÒÒªÇóÆäÖд×ËáµÄŨ¶ÈΪ0.20mol¡¤L1£¬Ðè
£
c(Ac-)c(Ac-)c(Ac-)?0.26 ?0.26 ½â£ºpH?4.74?lg?5.00 lg0.20.2c(HAc)£1£1-c(Ac)=0.36 mol¡¤L ÐèÓÃ1.0mol¡¤L
µÄ´×ËáÈÜÒººÍ¹ÌÌåNaAc23H2O¸÷¶àÉÙ£¿
µÄ´×ËáÈÜÒº100mL,¹ÌÌåNaAc23H2O 20.5g
6-20£®ÏÂÁÐÈõËá»òÈõ¼îÄÜ·ñÓÃËá¼î±ê×¼ÈÜÒºÖ±½ÓµÎ¶¨£¿ÈôÄܵ樣¬ÖÕµãʱӦѡʲô×÷ָʾ¼Á£¿¼ÙÉèËá¼î±ê×¼ÈÜÒººÍ¸÷ÈõËá¡¢Èõ¼îµÄ³õʼŨ¶È¶¼Îª0.1 mol¡¤L1¡£
£
£¨1£©HCN £¨2£©HF £¨3£©CH2ClCOOH £¨4£©±½·Ó £¨5£©CH3NH2 £¨6£©Áù´Î¼×»ùËİ· £¨7£©ßÁठ£¨8£©NaCN £¨9£©NH4Cl £¨10£©NaAc ½â£º
6-21£®ÏÂÁи÷¶àÔªÈõËá(¼î)ÄÜ·ñÓÃËá¼î±ê×¼ÈÜÒºÖ±½ÓµÎ¶¨£¿ÈôÄܵ樣¬Óм¸¸öͻԾ£¿¸÷¼ÆÁ¿µãʱӦѡʲô×÷ָʾ¼Á£¿¼ÙÉèËá¼î±ê×¼ÈÜÒººÍ¸÷ÈõËá¡¢Èõ¼îµÄ³õʼŨ¶È¶¼Îª0.1 mol¡¤L-1¡£
£¨1£©¾ÆÊ¯Ëá £¨2£©ÄûÃÊËá £¨3£©ÒÒ¶þ°·(H2NCH2CH2NH2) £¨4£©Na2C2O4 £¨5£©Na3PO4 £¨6£©Na2S ½â£º