2k+44
∴y1+y2=k(x1+x2)-2k=k·2-2k=,
2
kk21
得到y0=,∴x0=2,
kk?12?可得P?2,?,
?kk?
3
∵PF=,∴2
?1-12?2+4=3,解得k2=2, ?k?k22??
∴k=2,直线方程为y=2(x-1), 即2x-y-2=0, 故答案为2x-y-2=0.
2k+44
∴y1+y2=k(x1+x2)-2k=k·2-2k=,
2
kk21
得到y0=,∴x0=2,
kk?12?可得P?2,?,
?kk?
3
∵PF=,∴2
?1-12?2+4=3,解得k2=2, ?k?k22??
∴k=2,直线方程为y=2(x-1), 即2x-y-2=0, 故答案为2x-y-2=0.