46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90
91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121
附录3：
model: sets:
v / 1.. 10/: u,D;
link( v, v):C,y, x; endsets
min = @sum( link: C*x);
@sum(v( I)| I #ne# 1: x(I, 1))=1; @sum(v( I)| I #ne# 1: x(1,I))=1; @FOR( v(K):
@sum( v( I)| I #ne# K: x( I, K))<1; @sum( v( J)| J #ne# K: x(K,J))<1); @FOR( v(K):
@bin(@sum( v( I)| I #ne# K: x( I, K)));
@bin(@sum( v( J)| J #ne# K: x(K,J)))); @sum(v(I)| I #ne#6 :x(I,6))=1; !@sum(v(I)| I #ne#10 :x(I,10))=1; !@sum(v(I)| I #ne#4 :x(I,4))=1; !@sum(v(I)| I #ne#2:x(I,2))=1; !@sum(v(I)| I #ne#3:x(I,3))=1; !@sum(v(I)| I #ne#5:x(I,5))=1; !@sum(v(I)| I #ne#8:x(I,8))=1; !@sum(v(I)| I #ne#7:x(I,7))=1; !@sum(link(I,J)|I #ne# J:x(I,J))>4 @sum(link(I,J)|I #ne# J:x(I,J)*D(J))>36 @sum(link(I,J)|I #ne# J:x(I,J)*D(J))<50; @for(v(I):
@sum(v(J): x(I,J))-@sum(v(J): x(J,I))=0); @for(v(I)|I #gt# 1:
@for( v( J)| J#gt#1 #and# I #ne# J: u(I)-u(J)+10*x(I,J)<=9)); @for( link: @bin( x)); @for( link: @gin( x)); data:
D=8,13,6,9,7,15,10,5,12,9;
C=0 50 999 40 25 999 30 999 50 999
50 0 30 999 35 50 999 60 999 999 999 30 0 15 999 30 50 25 999 60 40 999 15 0 45 30 55 20 40 65 25 15 999 45 0 60 10 30 999 55 999 50 30 30 60 0 25 55 35 999 30 999 50 999 10 25 0 30 45 60 999 60 25 20 30 55 30 0 10 999 20 999 999 40 999 15 25 45 0 20 35 20 10 45 20 999 60 999 30 0
; enddata end
附录4：
clear; clc;
M=10000;%不能直接到达是将距离赋值给M a(1,:)=[0,50,M,40,25,M,30,M,50,M]; a(2,:)=[50,0,30,M,35,50,M,60,M,M]; a(3,:)=[M,30,0,15,M,30,50,25,M,60]; a(4,:)=[40,M,15,0,45,30,55,20,40,65]; a(5,:)=[25,15,M,45,0,60,10,30,M,55]; a(6,:)=[M,50,30,30,60,0,25,55,35,M]; a(7,:)=[30,M,50,M,10,25,0,30,45,60]; a(8,:)=[M,60,25,20,30,55,30,0,10,M]; a(9,:)=[20,M,M,40,M,15,25,45,0,20];
a(10,:)=[35,20,10,45,20,M,60,M,30,0];%建立a矩阵
path=zeros(length(a)); %建立一个与矩阵a同大小的全零矩阵for i=1:10 for j=1:10
path(i,j)=j; %用path矩阵记录走过的点 end end
for k=1:10 for i=1:10 for j=1:10
if a(i,j)>a(i,k)+a(k,j) a(i,j)=a(i,k)+a(k,j);
path(i,j)=path(i,k); % floyd算法 end end end end a, path
i1=input('请输入起点'); i2=input('请输入终点'); disp(i1); while i1~=i2 i1=path(i1,i2); disp(i1); end; a =
0 40 55 40 25 55 30 55 50 70 50 0 30 45 35 50 45 55 65 85 55 30 0 15 55 30 50 25 35 55 40 45 15 0 45 30 50 20 30 50 25 15 45 45 0 35 10 30 40 55 55 50 30 30 35 0 25 50 35 55 30 25 50 50 10 25 0 30 40 60
30 45 25 20 30 25 30 0 10 30 20 40 30 40 35 15 25 45 0 20 35 20 10 25 20 40 30 35 30 0 path =
1 5 4 4 5 7 7 5 9 9 1 2 3 3 5 6 5 3 3 3 4 2 3 4 8 6 7 8 8 8 1 3 3 4 5 6 8 8 8 8 1 2 2 4 5 7 7 8 8 10 7 2 3 4 7 6 7 4 9 9 1 5 3 8 5 6 7 8 8 10 9 5 3 4 5 9 7 8 9 9 1 10 10 4 7 6 7 8 9 10 1 2 3 3 5 3 5 3 9 10 请输入起点1 请输入终点2 1 5 2