µÚ1Õ ÍÑÁò·ÖÎö¹æ³Ì
1.1
1.1.1 1.1.2 1.1.3 1.1.4 1.1.5 1.1.6
·ÖÎöÏîÄ¿
ʯ»Òʯ·ÖÎöÖ¸±ê£ºCaCO3£¬SiO2£¬MgO£¬AL2O3 ʯ»Òʯ½¬Òº·ÖÎöÖ¸±ê£ºº¬¹ÌÁ¿£¬Ï¸¶È ʯ¸àäöÁ÷Æ÷µ×Òº¡¢ÒçÁ÷Òº£ºº¬¹ÌÁ¿ ·ÏË®äöÁ÷Æ÷µ×Òº¡¢ÒçÁ÷Òº£ºº¬¹ÌÁ¿
ʯ¸à·ÖÎöÖ¸±ê£º±íÃæË®·Ö¡¢ CaSO4¡¤2H2O¡¢ CaCO3¡¢ CaSO3¡¤1/2H2O¡¢CL¡¢F¡¢MgO
ʯ¸à½¬Òº·ÖÎöÖ¸±ê£¨ÎüÊÕËþ£©£ºº¬¹ÌÁ¿¡¢PH¡¢ CaSO4¡¤2H2O¡¢ CaCO3¡¢ CaSO3¡¤1/
£
2H2O¡¢CL
£
£
1.2
1.2.1 1.2.1.1
ÊÔÑùµÄ²É¼¯ÓëÖÆ±¸
ÊÔÑù²É¼¯
ʯ»ÒʯµÄ²ÉÑù£º°´GB/T15057.1-94½øÐÐ
Ò»¸ö³µÏᣨ»òÒ»´¬£©ÎªÒ»¸ö²ÉÑùµ¥Ôª¡£Ã¿¸ö³µÏᣨ»òÒ»´¬£©²É¼¯Ò»¸öÑùÆ·¡£²ÉÑùµãÓ¦Àë³µ±Ú¡¢µ×²¿²»Ð¡ÓÚ0.3Ãס£Àë±íÃæ²»Ð¡ÓÚ0.2Ãס£²É¼¯µÄÑùÆ·³ä·Ö»ìºÏ³ÉÒ»¸öÑùÆ·£¬ÔÙ½øÐÐÖÆÑù¡£²ÉÑùµã²¼ÖÃͼÈçÏ£º
Æû³µ³µÏá 1.2.1.2 ½¬ÒºµÄ²ÉÑù£¨°üÀ¨Ê¯»Òʯ½¬Òº£¬Ê¯¸à½¬Òº£¬ÍÑÁòËþÄÚ½¬Òº£©
ÔÚ¸÷É豸Éè¼Æ°²×°µÄ²ÉÑùµã´¦²ÉÑù£ºÊ¯»Òʯ½¬Òº²ÉÑùµãÔÚ0Ã×ʯ»Òʯ½¬Òº¹ÞÅÔ£»Ê¯¸à½¬Òº²ÉÑùµãÔÚ14Ãׯ½Ì¨Ê¯¸àÍÑË®»úÅÔ£»ÍÑÁòËþÄÚ½¬Òº²ÉÑùµãÔÚÍÑÁòËþ¹ÞÅÔ0Ã×´¦¡£
1.2.1.3 ʯ¸à²ÉÑù£ºÊ¯¸à²ÉÑùÔÚÕæ¿ÕƤ´ø»ú¡£
ËùÓÐÑùÆ·²ÉÑùǰ£¬¶¼±ØÐë°Ñ²ÉÑùµãÄڵIJÐÁôÎï³åÏ´µô£¬Ê¹²É¼¯µÄÑùÆ·¾ßÓдú±íÐÔ¡£
1.2.2 1.2.2.1
ÊÔÑùÈÜÒºµÄÖÆ±¸ ʯ»ÒʯÊÔÑùÈÜÒºÖÆ±¸
³ÆÈ¡Ô¼0.2gÊÔÑù£¬¾«È·ÖÁ0.0001g£¬ÖÃÓÚ100mL¾ÛËÄ·úÒÒÏ©ÉÕ±ÖУ¬ÓÃÉÙÐíË®ÈóʪÊÔÑù£¬¸ÇÉϱíÃæÃó£¬ÑØÉÕ±×ìµÎ¼Ó1+1µÄÑÎËáÈÜÒº£¬´ý·´Ó¦Í£Ö¹ºó£¬¹ýÁ¿1mL³åÏ´±íÃæÃóºÍÉÕ±±Ú¡£¼Ó4mLÇâ·úËáºÍ2mL¸ßÂÈËᣬÖÃÓÚµçÈȰåÉϵÍμÓÈȽü¸É¡£È¡ÏÂÉÕ±£¬ÉÔÀ䣬ÓÃÉÙÐíË®³åÏ´ÉÕ±±Ú£¬¼ÌÐø¼ÓÈȰ×ÑÌð¾¡ÖÁ¸É¡£ÉÔÀ䣬¼Ó3mLÑÎËᣬ¼ÓÈÈÈܽâÖÁÇåÁÁ£¬ÀäÈ´ÖÁÊÒΣ¬ÒÆÈë250mLÈÝÁ¿Æ¿ÖУ¬ÓÃˮϡÊÍÖÁ¿Ì¶È£¬Ò¡ÔÈ¡£´Ë¼´Îª·ÖÎöÓÃÊÔÑù¡£Í¬Ê±ÖƱ¸¿Õ°×Ñù¡£
»¯Ñ§ÔËÐйæ³Ì£¨B°æ£©
1.2.2.2 FGDµº½¬ÒºµÄÖÆ±¸
´ÓFGD²ÉÑù¿ÚÈ¡³öµÄ½¬Òº³ÃÈȾ¡¿ìÓúãÎÂÏäË͵½ÊµÑéÊÒ£¬ÂíÉϲⶨÃܶȣ¬ÓÃG4²£Á§Ûá¹ø¹ýÂ˵½ÈÝÁ¿Æ¿ÖУ¬ÖƱ¸ÂËÒº¡£
1.2.2.3 ʯ¸àÊÔÑùÈÜÒºµÄÖÆ±¸
³ÆÈ¡Ô¼2g¸Éʯ¸à£¬¾«È·ÖÁ0.0001g£¬ÖÃÓÚ250mLÉÕ±ÖУ¬¼ÓÈë100mLµÄ250mLÈÝÁ¿Æ¿ÖкÍ10mL 30%µÄÑÎËáÈÜÒº£¬Öó·Ð30·ÖÖÓ£¬ÓÃÂýËÙ¶¨Á¿ÂËÖ½¹ýÂË£¬ÂËÒºÀäÈ´ºóÒÆÈë250mLÈÝÁ¿Æ¿ÖУ¬¼Ó250mLÈÝÁ¿Æ¿ÖÐÖÁ¿Ì¶È¡£
1.3
1.3.1
·ÖÎö·½·¨
pH
ÓÃpH¼Æ²âÁ¿²¢¼ÇÏÂζÈ
1.3.2 µçµ¼ÂÊ
Óõ絼ÂʲâÁ¿²¢¼ÇÏÂζȡ£
1.3.3 ÃܶȵIJⶨ£º
²â¶¨ÑùƷζȣ¬³ÆÁ¿ÃÜ¶ÈÆ¿ÖØÁ¿M£¬È¡½¬ÒºÓÚÒÑÖªÌå»ýV£¨mL£©µÄÃÜ¶ÈÆ¿ÖУ¬³ÆÖصÃM1£¨g£©¡£
ÃܶÈg/cm3»òg/ml?1.3.4
???MV?M?
1¹Ìº¬Á¿µÄ²â¶¨£¨ÊʺÏÓÚ¸÷ÖÖ½¬ÒºÖй̺¬Á¿µÄ²â¶¨£©
³ÆÁ¿ÒѺãÖØµÄG4²£Á§³éÂËÛá¹øm1£¬¹ýÂËÃܶȲⶨʱÓõĽ¬ÒºÑùÆ·£¬ÒÑÖªÖØÁ¿m£¬»òÒÑÖªÌå»ýV£¨Ôòm=¦Ñ¡ÁV£©£¬²¢Ó÷ÖÎö´¿±ûͪ³åÏ´3´Î£¨ÔÚÂÈ»¯ÎﺬÁ¿´óÓÚ20000mg/Lʱ£¬ÏÈÓÃÔ¼20mL³ýÑÎË®³åÏ´3´Î£¬È»ºóÓñûͪ³åÏ´£©È»ºóÔÚ50¡æµÄ¸ÉÔïÏäÖиÉÔֱÖÁºãÖØm2£¨Ç°ºóÁ½´ÎÖÊÁ¿²î²»ÄÜ´óÓÚ0.0004mg£©¡£
(m?m1)¹Ìº¬Á¿£¥£½2?100
m1.3.5
Á£¾¶·Ö²¼
È¡3·ÝÊÔÑù£¬Ò»·ÝÊÔÑé²â¶¨½¬ÒºÃܶȺͺ¬¹ÌÁ¿£¬Æä²âÊÔ·½·¨Í¬ÉÏ£¬ÆäÓàÁ½·ÝÊÔÑù·Ö±ðÓÃÓڲⶨ£¾60¦ÌmºÍ£¾45¦Ìmϸ¶ÈµÄ²â¶¨¡£
ÆäÓàÁ½·Ý½¬Òº·Ö±ðÓÃ60¦ÌmºÍ45¦Ìm±ê׼ɸ½øÐÐʪʽ¹ýÂË£¬ÓÃË®³ä·ÖµÄ½øÐÐÁÜÏ´£¬½«É¸ÉϲÐÁôÎïÏ´ÖÁ0.45¦ÌmÒѺãÖØµÄÂËÖ½Óò£Á§¹ýÂËÆ÷¹ýÂË£¬È»ºóСÐÄÈ¡ÏÂÂËÖ½£¬ÖÃÓÚË®·Ö¿ìËٲⶨÒÇÉÏÔÚ50¡æ½øÐкæ¸ÉÖÁºãÖØ¡£È»ºó³ÆÁ¿Æä²ÐÁôÎïÖØÁ¿£¬Æäϸ¶ÈµÄ°Ù·Öº¬Á¿°´ÏÂʽ¼ÆËã¡£
R60?m1
V1?¦Ñ?¹Ìº¬Á¿¡¤2¡¤
R40?m2
V2?¦Ñ?¹Ìº¬Á¿R60¡ª¡ªÁ£¾¶´óÓÚ60¦ÌmµÄ°Ù·Öº¬Á¿£¬£¥ R40¡ª¡ªÁ£¾¶´óÓÚ45¦ÌmµÄ°Ù·Öº¬Á¿£¬£¥ m1¡ª¡ª60¦Ìm±ê׼ɸɸÉÏÎïÖÊÁ¿£¬g m2¡ª¡ª45¦Ìm±ê׼ɸɸÉÏÎïÖÊÁ¿£¬g V1¡ª¡ªÓÃÓڲⶨR60µÄ½¬ÒºÌå»ý£¬mL V2¡ª¡ªÓÃÓڲⶨR45µÄ½¬ÒºÌå»ý£¬mL ¦Ñ¡ª¡ª½¬ÒºÃܶȣ¬g/mL ¹Ìº¬Á¿¡ª¡ª½¬ÒºµÄ¹ÌÌ庬Á¿£¬£¥
1.3.6
ÑÎËá²»ÈÜÎﺬÁ¿µÄ²â¶¨
½«´ÉÛáÛö·ÅÈëÂí¸¥Â¯ÖÐÔÚ800¡æÉÕÖÁºãÖØ£¬³ÆµÃ¾»ÖØÎªm1g£¬½«ÊÔÑùµÄ²»ÈÜÎïmg·ÅÈëÂí¸¥Â¯ÖÐÔÚ800¡æÉÕÖÁºãÖØ£¬³ÆµÃ¾»ÖØÎªm2g¡£
²»ÈÜÎﺬÁ¿£½?m2£m1??100m£¥
m¡ª¡ªÊÔÑùµÄ×ÜÖØÁ¿£¬g m2¡ª¡ª´ÉÛáÛöµÄÖØÁ¿£¬g
m1¡ª¡ª´ÉÛáÛöºÍÊÔÑù²»ÈÜÎïµÄ»ìºÏÖØÁ¿£¬g
1.3.7 1.3.7.1
ÂȺ¬Á¿µÄ²â¶¨
·½·¨Ò»£¨ÊʺϽ¬Òº¼°·ÏË®ÖÐÂȺ¬Á¿µÄ²â¶¨£©
ÓÃÒøµç¼«ºÍ²Î±Èµç¼«£¬ÎüÈ¡VmL£¨Ò»°ãΪ10mL£©ÈÜÒº£¬È»ºó¼ÓÈë50mL³ýÑÎË®ºÍ2mL1£º4ÁòËá½øÐлìºÍ£¬ÔÚµçλµÎ¶¨ÒÇÉÏÑ¡ÓÃDM141µç¼«£¬Æô¶¯µçλµÎ¶¨ÒÇ301µÎ¶¨³ÌÐò£¬ÓÃ0.1NAgNO3±ê×¼ÈÜÒºµÎ¶¨Öյ㡣¼Ç¼ÏûºÄAgNO3ÈÜÒºV1mL£¬Èç¹ûÓдóÁ¿µÄÑÇÏõËáÑεÄÇé¿öÏ£¬µÎ¶¨Ç°±ØÐëʹÓÃH2O2½øÐÐÑõ»¯£¨¼ÓÈë0.5mL¡«1mL H2O2£©¡£
Cl??V1?0.1?35.45?1000
VV1¡ª¡ªAgNO3±ê×¼ÈÜÒºÏûºÄÁ¿£¬mL V¡ª¡ªÊÔÑùÌå»ý£¬mL
1.3.7.2
·½·¨¶þ£¨ÊʺÏʯ¸à¹ÌÌåÖÐÂȺ¬Á¿µÄ²â¶¨£©