人教版高中数学必修一2.2.1.2课时练习习题(含答案解析)

2.2.1.2

一、选择题

1.下列式子中正确的个数是( ) ①loga(b2-c2)=2logab-2logac ②(loga3)2=loga32 ③loga(bc)=(logab)·(logac) ④logax2=2logax

A.0 B.1 C.2 D.3 [答案] A

2.如果lgx=lga+2lgb-3lgc,则x等于( ) A.a+2b-3c ab2

C.3 c[答案] C

ab2

[解析] lgx=lga+2lgb-3lgc=lg3,

cab2

∴x=3,故选C.

c

3.(2010·四川理,3)2log510+log50.25=( ) A.0 C.2 [答案] C

[解析] 2log510+log50.25=log5100+log50.25=log525=2. 4.已知a=log32,那么log38-2log36用a表示为( ) A.a-2

B.5a-2 D.3a-a2-1

B.1 D.4

B.a+b2-c3 2ab

D. 3c

C.3a-(1+a)2 [答案] A

[解析] 由log38-2log36=3log32-2(log32+log33)=3a-2(a+1)=a-2. 5.

A.2+5 C.2+

5 2

的值等于( )

B.25 D.1+

5 2

[答案] B

[解析] 据对数恒等式及指数幂的运算法则有:

6.与函数y=10lg(x-1)

的图象相同的函数是( ) A.y=x-1 B.y=|x-1| C.y=x2-1

x+1

D.y=(

x-1)2x-1

[答案] D [解析] y=10lg(x

-1)

=x-1(x>1),故选D.

7.已知f(logx)=x,则f(1

22)=( )

A.1

4

B.1

2 C.2

2

D.2 [答案] D

[解析] 令log11

2x=2,∴x=2,∴f(2

)=2.

8.如果方程lg2x+(lg2+lg3)lgx+lg2·lg3=0的两根为x1、x2,那么x1·x2的值为( A.lg2·lg3 B.lg2+lg3 C.-6

D.16

[答案] D

[解析] 由题意知lgx1和lgx2是一元二次方程u2+(lg2+lg3)u+lg2·lg3=0的两根∴lgx1+lgx2=-(lg2+lg3), 即lg(x11

1x2)=lg6,∴x1x2=6.

9.(09·湖南文)log22的值为( ) A.-2 B.2 C.-1

2

D.12

[答案] D

1

[解析] log1

22=log222=2. 10.(09·江西理)函数y=ln(x+1)

-x2-3x+4的定义域为( )

A.(-4,-1) B.(-4,1) C.(-1,1)

D.(-1,1]

[答案] C

) ??x+1>0

[解析] 要使函数有意义,则需?2,

?-x-3x+4>0???x>-1

即?,解得-1

二、填空题

11.log6[log4(log381)]=________. [答案] 0

[解析] log6[log4(log381)]=log6(log44)=log61=0.

12.使对数式log(x-1)(3-x)有意义的x的取值范围是________. [答案] 1

[解析] y=log(x-1)(3-x)有意义应满足 3-x>0??

?x-1>0??x-1≠1

,解得1

13.已知lg3=0.4771,lgx=-3.5229,则x=________. [答案] 0.0003

[解析] ∵lgx=-3.5229=-4+0.4771 =-4+lg3=lg0.0003,∴x=0.0003.

3

14.已知5lgx=25,则x=________,已知logx8=,则x=________.

2[答案] 100;4

[解析] ∵5lgx=25=52,∴lgx=2,∴x=102=100,

32

3

∵logx8=,∴x2=8,∴x=83=4.

2

15.计算:

(1)2log210+log20.04=________; lg3+2lg2-1(2)=________;

lg1.2(3)lg23-lg9+1=________; 1

(4)log18+2log13=________; 366(5)log6

11

-2log63+log627=________. 123

10

[答案] 2,1,lg,-1,-2

3

[解析] (1)2log210+log20.04=log2(100×0.04)=log24=2 lg3+2lg2-1lg(3×4÷10)lg1.2(2)===1

lg1.2lg1.2lg1.2

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