苏大 基础物理(上)题库 试卷及答案

BP?B1P?B2[P??0I1?0I22?0I???4.0?10?5T2?x2?(d?x)?d??r1?r2??I?0I2?(2)解:???B?dS???01??ldxr12?x2?(d?x)???Ilr?r?Ild?r?01ln12?02ln2?2?d?r1?r2r1?

?0I1ld?r1ln?2.2?10?6韦伯?r1??d?d?6、解:(1)???Er?dS?? ,2?r?E?dtdt1d?SdB?r2dBrdB0.1?0.1E?????????5?10?3V/m2?rdt2?rdt2?rdt2dt2顺时针沿圆周的切向?1d?SdB(2)I???????1.57mARRdrRdt(3)U?2?rE?3.14?10?3V

苏州大学普通物理(一)上课程(04)卷参考答案 共2页

一、填空:(每空2分,共40分) 1、-2 rad/s2,425 rad,40 s 2、Ep?1E?0.5?10?5J,Ek?E?Ep?1.5?10?5J 414??0Q??,?U?d 5、E?R?0?03、1.3 m/s2,1.9 m/s 4、E?0,U??6、I?0,Uac??,Uab?? 7、8、B??01LI,MI1I2 2rI 22?R???39、M?ISB?0.003N?m,30(或150),m?IS?5?10二、计算题:(每小题10分,共60分) 1、Ek1?A?m2

1212I?1?1.97?104J,Ek2?I?2?2.19?103J 224每冲一次飞轮所做的功A?Ek1?Ek2?1.75?10J

2、设平面简谐波的波长为?,坐标原点处的质点振动初相位为?0,则该列平面简谐波的表达式可写成:

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y?0.1cos(7?t?2?x???0)0.1

t?1.0s时,ya?0.1cos[7??2?????0]?0此时a质点向y轴负方向运动,于是7??0.2????0??2

而此时b质点正通过y?0.05m处向y轴正方向运动0.2??yb?0.1cos?7??2???0??0.05???7??2?0.2???0???3 ②

联立①,②式得:??0.24m,?0??该平面波的表达为

17??(?0?) 3317?]30.12

?x?或y?0.1cos[7?t??]0.1233、(1)C?y?0.1cos[7?t??x?2?44??F 2?434?600?C?800?C3Q800?CU1???400VC12?FQ?CU?U2?Q800?C??200VC24?F(2)C??C1?C2?2?F?4?F?6?FQ??2?800?C?1600?CU??Q?1600??266.7VC?6Q1??2?266.7?10?6?533.3?C??4?266.7?10?6?1066.7?CQ24、dR??

?drdr? R???22?a2?a2?r2?r5、解:在平面S上取面元dS,长为l宽为dr

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