看不惯那些家伙。 高频电子第五版
3?1解：f0?1MHz2Δf0.7?1?106?990?103?10(kHz)f01?106Q???10032Δf0.710?10取R?10Ω则L?C?QR?01?100?10?159(?H)2?3.14?1061?159(pF)?02L(2?3.14?106)2?159?10?6
113?2解：(1)当?01?或ω?时，产生并联谐振。02L1C1L2C2?(2)当?01?(3)当?01?1或ω02?L1C11或ω02?L1C11时，产生串联谐振。L2C21时，产生并联谐振。L2C2
1L1)R2??jω0LR(1?2)R2?Ljω0CCω0LCC?R3?3证明：Z???112RR?jω0L?R?2R?jω0L(1?2)jω0Cω0LC 223?4解：1?由?15?C??1605??450?C?535得C?40pF(R?jω0L)(R?由?12?C??16052??100?C?5352得C?-1pF?不合理舍去?故采用后一个。2?L?3?
L C C’
11??180?μH??02?C?C???2?3.14?535?103?2??450?40??10?12
3?5解：Q0?11??2126-12?0C0R2?3.14?1.5?10?100?10?5L0?11??112?μH?226-12?0C0?2?3.14?1.5?10?100?10Vom1?10-3Iom???0.2?mA?R5VLom?VCom?Q0VSm?212?1?10-3?212?mV?113?6解：L?2??253?μH??0C?2?3.14?106?2?100?10?12
Q0?VC10??100VS0.1C?CX11?2??100?pF??CX?200pFC?CX?0L?2?3.14?106?2?253?10?62?3.14?106?253?10?62?3.14?106?253?10?6RX?????47.7?Ω?QQ02.50.1100?0L?0L11?47.7?j?47.7?j796?Ω?6?12?0CX2?3.14?10?200?10113?7解：L?2??20.2?μH?ω0C?2?3.14?5?106??50?10?12ZX?RX?jf05?106100Q0???2Δf0.7150?10332Δf1002??5.5?5??10620ξ?Q0???6f035?103??2?2?f0.7，则Q??因2Δf0.721kΩ电阻。 0?0.5Q0，故R?0.5R，所以应并上2πf0CωC3?8证明：4πΔf0.7C??0?g?f02Δf0.7Q
?C?C0?C1?5??20?20?20?18.3?pF?3?9解：C?Ci?2C2?C0?C120?20?20f0?11??41.6?MHz??6?122πLC2?3.140.8?10?18.3?10L?100?C120.8?10?6?20.9?kΩ??20?20??10?1222RP?Q0?C2?C0?C1??20?20?20??R??RiRP?R?1020.9???5?5.88?kΩ???0C20??1??R?5.88?103QL???28.26?6ω0L2?3.14?41.6?10?0.8?102Δf0.7f041.6?106???1.48?MHz?QL28.2
3?12解：1?Zf1?02?Zf1?03?Zf1?R
3?13解：1?L1?L2?C1?C2?ρ1?01103??159?μH?62?3.14?1011??159?pF?226?6?01L1?2?3.14?10??159?10ηR1?20M?1??3.18?μH?6?012?3.14?102?Zf1??01M?2?R2?2?3.14?10?6?3.18?10?6??20?Ω?202L1159?10?6ZP???25?kΩ??12?R1?Rf1?C1?20?20??159?103?Q1??01L1R1?Rf12?3.14?106?159?10?6??2520?204?2Δf0.7??5?C2f0f0106?20?2?2?2??28.2?kHz?Qρ1R110312????02L2?1?2?3.14?950?10?32?159?10?6?177?pF??1?Z22?R2?j??L??021?C???022??1???20?j?2?3.14?106?159?10?6??20?j1006?12?2?3.14?10?177?10??Zf1??01M?2?Z22?2?3.14?10??6?3.18?10?6??0.768?j3.84?Ω?20?j10062
3?15解：?R?L159?10??20????R13?12RPC50?10?159?10?Rf1?0?M?0f0106Q?2?2?10032?f0.714?10