4-工程经济学概论习题答案

工程经济学概论习题答案

第4章 投资方案的评价指标

5、某项目期初(第1年初)固定资产投资200万元,投产时需要流动资金30万元。若该项目从第2年初投资并达到设计能力,每年经营费为50万元,该项目服务年限为10年,届时残值为10万元,若年利率为10%,试计算该项目总费用的现值。√ 解:

不考虑流动资金回收:

PC=200+30 (P/F, 10%, 1)+50 (P/A, 10%, 10)-10 (P/F, 10%, 10) =200+30×0.9091+50×6.1446-10×0.3855=530.6 (万元)

考虑流动资金回收:

PC=200+30 (P/F, 10%, 1)+50 (P/A, 10%, 10) -40 (P/F, 10%, 10) =200+30×0.9091+50×6.1446-40×0.3855 =519.083 (万元)

6、根据表4-3所列的现金流量,假定基准贴现率为10%。计算这两个现金流量的净现值、将来值和年度等值。√

表4-3 习题6的现金流量表 单位:万元 年末 方案 A B 0 -100 -100 1 50 40 2 50 40 3 50 60 4 50 60 解:

NPVA=-100+50 (P/A, 10%, 4)=-100+50×3.1699=58.5 (万元) NPVB=-100+40 (P/A, 10%, 2) +60 (P/A, 10%, 2) (P/F, 10%, 2)

=-100+40×1.7355+60×1.7355×0.8262=55.47 (万元) NFVA= NPVA (F/P, 10%, 4)=58.5×1.4641=85.6 (万元) NFVB= NPVB (F/P, 10%, 4) =55.5×1.4641=81.2 (万元) NAVA= NPVA (A/P, 10%, 4) =58.5×0.3155=18.46 (万元) NAVB= NPVB (A/P, 10%, 4) =55.5×0.3155=17.5 (万元)

8、2000年发行面值为1000元的某债券,每年可按面值的6%支付利息,5年后归还债券面值,求在发行时购买债券的内部收益率。2001年购买这种债券的价格是1070元,求2001年购买债券的内部收益率。√ 解:

(1) NPV=-1000+60 (P/A, i, 5) +1000 (P/F, i, 5)=0 i=6%

NPV=-1000+60 (P/A, 6%, 5) +1000 (P/F, 6%, 5)

=-1000+60×4.2124+1000×0.7473=0.044 (万元)

1

i=7%

NPV=-1000+60 (P/A, 7%, 5) +1000 (P/F, 7%, 5)

=-1000+60×4.1002+1000×0.7130=-40.988 (万元)

IRR?6%?0.044?1%?6.00%

0.044?40.988

(2) NPV=-1070+60 (P/A, i, 4) +1000 (P/F, i, 4)

i=4%

NPV=-1070+60 (P/A, 4%, 4) +1000 (P/F, 4%, 4) =-1070+60×3.6299+1000×0.8548=2.594 (万元)

i=6%

NPV=-1070+60 (P/A, 6%, 4) +1000 (P/F, 6%, 4) =-1070+60×3.4651+1000×0.7921=-69.994 (万元)

IRR?4%?2.594?2%?4.07%

2.594?69.994

9、王先生现在以30万元买进一处房产,用以出租,如果年租金收入为3.2万元,年物业管理费等支出为2000元,预期10年后可以以25万元的价格卖出。问出售这一房的税前内部收益率为多少?若王先生自己使用,可接受的收益水平为8%,问拥有该房产的等额年成本为多少?√ 解:

(1) NPV=-30+ (3.2-0.2) (P/A, i, 10) +25 (P/F, i, 10) =0

i=8%

NPV=-30+ (3.2-0.2) (P/A, 8%, 10)+25 (P/F, 8%,10) =-30+3×6.7101+25×0.4632=1.7103 (万元)

i=10%

NPV=-30+ (3.2-0.2) (P/A, 10%, 10)+25 (P/F, 10%,10) =-30+3×6.1446+25×0.3855=-1.9287 (万元)

IRR?8%?1.7103?2%?8.94%

1.7103?1.9287

(2) AC=PC(A/P, 8%, 10)

=[30+0.2× (P/A, 8%, 10) -25 (P/F, 8%, 10)] ×(A/P, 8%, 10) =(30 +0.2×6.7101-25×0.46320)×0.1490 =19.76202×0.149=2.9445 (万元) 或

AC=30× (A / P, 8%, 10)+0.2-25× (A/F, 8%, 10) =30× 0.1490+0.2-25× 0.0690=2.945 (万元)

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