楂?/p>
涓?/p>
鍖?/p>
瀛?/p>
鏂?/p>
绋?/p>
寮?/p>
姹?/p>
鎬?/p>
鏃犳満鍖栧鍙嶅簲寮?/p>
2
銆?/p>
2Na+2H
2
O=2NaOH+H
2
鈫?/p>
鈽?/p>
2K+2H
2
O=2KOH+H
2
鈫?/p>
3
銆?/p>
2Na
2
O
2
+2H
2
O=4NaOH+O
2
鈫?/p>
4
銆?/p>
2Na
2
O
2
+2CO
2
=2Na
2
CO
3
+O
2
7
銆佹阿姘у寲閽犲拰纰抽吀姘㈤挔鍦ㄦ憾娑蹭腑鍙嶅簲鐨勭瀛愭柟绋嬪紡涓猴細
OH
-
+HCO
3
-
=CO
3
2-
+H
2
O
12
銆佹隘姘旀憾浜庢按锛堟柊鍒舵隘姘翠腑鍚?/p>
Cl
2
.HClO.H
2
O .H
+
.Cl
-
.ClO
-
.OH
-
锛夛細
Cl
2
+H
2
O=HCl+HClO
鈽?/p>
Cl
2
+2NaOH=NaCl+NaClO+H
2
O
13
銆佹姘吀瑙佸厜鍒嗚В锛堝己姘у寲鍓傘�佹潃鑿屾秷姣掞紝婕傜櫧鍓傦級锛?/p>
2HClO
鍏夌収
2HCl+O
2
鈫?/p>
14
銆?/p>
Ca(ClO)
2
+CO
2
+H
2
O=CaCO
3
+2HClO
15
銆?/p>
MnO
2
+4HCl(
娴?/p>
)
MnCl
2
+Cl
2
鈫?2H
2
O
17
銆?/p>
2F
2
+2H
2
O=4HF+O
2
Cl
2
+H
2
O=HCl+HClO
Br
2
+H
2
O=HBr+HBrO
19
銆?/p>
2Al+2NaOH+2H
2
O=2NaAlO
2
+3H
2
鈫?/p>
Al
2
O
3
+2NaOH=2NaAlO
2
+H
2
O
Al(OH)
3
+NaOH=NaAlO
2
+2H
2
O
23
銆?/p>
H
2
O
2
鐨勫垎瑙ｏ細
2H
2
O
2
2
MnO
2H
2
O+O
2
鈫?/p>
*H
2
S
涓?/p>
SO
2
鐨勫弽搴旓細
2H
2
S+SO
2
=3S+2H
2
O
25
銆?/p>
2SO
2
+O
2
鍌寲鍓傘�佲柍
2SO
3
27
銆?/p>
Cu+2H
2
SO
4
(
娴?/p>
)
CuSO
4
+SO
2
鈫?/p>
+2H
2
O
28
銆?/p>
C+2H
2
SO
4
锛堟祿锛?/p>
CO
2
鈫?/p>
+2SO
2
鈫?/p>
+2H
2
O
30
銆?/p>
SiO
2
+2C
楂樻俯
Si+2CO
鈫?/p>
33
銆?
鍌寲鍓?/p>
楂樻俯銆侀珮鍘?
2
2
N
+3H
3
2NH
34
銆?/p>
N
2
+O
2
鏀剧數
ChemPaster
2NO
2NO+O
2
=2NO
2
35
銆?/p>
3NO
2
+H
2
O=2HNO
3
+NO
45
銆?/p>
4NH
3
+5O
2
4NO+6H
2
O
47
銆佺敤娴撶洂閰告楠屾皑姘旓紙鐧界儫鐢熸垚锛夛細
NH
3
+HCl=NH
4
Cl
48
銆?/p>
(NH
4
)
2
SO
4
+2NaOH
Na
2
SO
4
+2NH
3
鈫?/p>
+2H
2
O
49
銆?/p>
NH
4
NO
3
+NaOH=NaNO
3
+NH
3
鈫?/p>
+H
2
O