1-2
鍥?/p>
涓?/p>
瀹?/p>
鍣?/p>
鍐?/p>
鍘?/p>
鍔?/p>
P=0.2
bar=2*
Pa
锛?/p>
鎵�
浠?/p>
鈭?/p>
鈻?/p>
P
鈭?/p>
=
鈭?/p>
20000-100000
鈭?
=8*
Pa
鎵�浠ヨ鏁颁负
8*
Pa
1-6
璁剧儫姘旂殑缁濆鍘嬪姏涓?/p>
P1
鈭?
P1+蟻gh=Po
,
鍙?
鈭?
h=L*
=0.1m,
鈭?
P1=
Po-800*9.8*0.1=745*133.3-784=98524.5 Pa
鈭寸儫姘旂殑缁濆鍘嬪姏涓?/p>
98524.5 Pa,
鐪熺┖搴︿负
Po- P1=784 Pa
銆?/p>
1-13
鈶村綋
B
瀹瑰櫒鍐呯殑鍘嬪姏澶т簬澶ф皵鍘嬫椂
+蟻gh=1.01*
+13.95*
*9.81*0.2=1.28*
Pa
鍙堚埖
=
+1.4*
=2.68*
Pa
鈶靛綋瀹瑰櫒鍐呯殑鍘嬪姏灏忎簬澶ф皵鍘嬫椂
-
蟻gh=1.01*
-13.95*
*9.81*0.2=73.63*
Pa
=
+1.4*
=2.136*