2019
骞撮珮鑰冨垎绫昏В鏋?/p>
---
鐞嗙患
锛堝寲瀛︼級
闈為�夋嫨棰橀儴鍒?/p>
锛?/p>
8.
閫熺巼
涓庡钩琛★級
澶囨敞锛?/p>
2019
骞撮珮鑰冨寲瀛︽垨鑰呯悊绉戠患鍚堬紙鍖栧锛夎瘯棰樼粺璁″強椤哄簭
锛堝叡
15
濂楋紝
31
鍦板尯锛?/p>
1
銆侊紙
1
濂楋級澶х翰鐗堝叏鍥藉嵎
锛堝箍瑗匡級
2
銆侊紙
1
濂楋紝
9
鍦板尯锛夋柊璇炬爣鍏ㄥ浗鍗?/p>
I(
鍐呰挋鍙ゃ�佸畞澶忥紱榛戦緳姹熴�佸悏鏋椼�佹渤鍗椼�佹渤鍖椼�佸北瑗裤�侀檿
瑗裤�佹箹鍗椼�佹睙瑗匡級
3
銆侊紙
1
濂楋紝
7
鍦板尯锛夋柊璇炬爣鍏ㄥ浗鍗?/p>
II
锛堣タ钘忥紝鏂扮枂锛涢潚娴枫�佺敇鑲冦�佽吹宸炪�佷簯鍗椼�佽窘瀹侊級
4
銆侊紙
4
濂楋紝
4
鍦板尯锛?/p>
4
涓洿杈栧競鍚勪竴濂楋細鍖椾含銆佸ぉ娲ャ�佷笂娴枫�侀噸搴?/p>
5
銆侊紙
8
濂?/p>
,8
鍦板尯锛夎嚜涓?/p>
28
锛庯紙
15
鍒嗭級
浜岀敳閱氾紙
CH
3
OCH
3
锛夋槸鏃犺壊姘斾綋锛屽彲浣滀负涓�绉嶆柊鍨嬭兘婧愩�傜敱鍚堟垚姘旓紙缁勬垚涓?/p>
H
2
銆?/p>
CO
鍜?/p>
灏戦噺鐨?/p>
CO
2
锛夌洿鎺ュ埗澶囦簩鐢查啔锛屽叾涓殑涓昏杩囩▼鍖呮嫭浠ヤ笅鍥涗釜鍙嶅簲锛?/p>
鐢查唶鍚堟垚鍙嶅簲锛?/p>
锛?/p>
i
锛?/p>
CO(g) + 2H
2
(g) = CH
3
OH(g)
鈻?/p>
H
1
= -
90.1kJ鈥ol
-1
锛?/p>
ii
锛?/p>
CO
2
(g) + 3H
2
(g) = CH
3
OH(g) + H
2
O(g)
鈻?/p>
H
2
= -
49.0kJ鈥ol
-1
姘寸叅姘斿彉鎹㈠弽搴旓細
锛?/p>
iii
锛?/p>
CO(g) + H
2
O(g) = CO
2
(g) + H
2
(g)
鈻?/p>
H
3
= -
41.1kJ鈥ol
-1
浜岀敳閱氬悎鎴愬弽搴旓細
锛?/p>
iV
锛?/p>
2 CH
3
OH(g) = CH
3
OCH
3
(g) + H
2
O(g)
鈻?/p>
H
4
= -
24.5kJ鈥ol
-1
鍥炵瓟涓嬪垪闂锛?/p>
锛?/p>
1
锛?/p>
Al
2
O
3
鏄悎鎴愭皵鐩存帴鍒跺浜岀敳閱氬弽搴斿偓鍖栧墏鐨勪富瑕佹垚鍒嗕箣涓�銆?/p>
宸ヤ笟涓婁粠閾濆湡鐭垮埗
澶囪緝楂樼函搴?/p>
Al
2
O
3
鐨勪富瑕佸伐鑹烘祦绋嬫槸
锛堜互鍖栧鏂圭▼寮忚〃绀猴級銆?/p>
锛?/p>
2
锛?/p>
鍒嗘瀽浜岀敳閱氬悎鎴愬弽搴?/p>
锛?/p>
iV
锛?/p>
瀵逛簬
CO
杞寲鐜囩殑褰卞搷
銆?/p>
锛?/p>
3
锛夌敱
H
2
鍜?/p>
CO
鐩存帴鍒跺浜岀敳閱氾紙鍙︿竴浜х墿涓烘按钂告皵锛夌殑鐑寲瀛︽柟绋嬪紡
涓?/p>
銆傛牴鎹寲瀛﹀弽搴斿師鐞嗭紝鍒嗘瀽澧炲姞鍘嬪己瀵圭洿鎺ュ埗澶囦簩鐢查啔鍙嶅簲鐨勫奖
鍝?/p>
銆?/p>
锛?/p>
4
锛夋湁鐮旂┒鑰呭湪鍌寲鍓傦紙鍚?/p>
Cu
鈥?/p>
Zn
鈥?/p>
Al
鈥?/p>
O
鍜?/p>
Al
2
O
3
锛夈�佸帇寮轰负
5.0MPa
鐨勬潯浠朵笅锛?/p>
鐢?/p>
H
2
鍜?/p>
CO
鐩存帴鍒跺浜岀敳閱氾紝缁撴灉濡備笅鍥炬墍绀恒�傚叾涓?/p>
CO
杞寲鐜囬殢娓╁害鍗囬珮鑰岄檷浣庣殑鍘?/p>
鍥?/p>
鏄?/p>
銆?/p>
锛?/p>
5
锛変簩鐢查啔鐩存帴鐕冩枡鐢垫睜鍏锋湁鍚姩蹇�佹晥鐜囬珮绛変紭鐐癸紝鍏惰兘閲忓瘑搴︾瓑浜庣敳閱囩洿鎺ョ噧
鏂欑數姹狅紙5.93kW鈥鈥g
-1
锛夈�傝嫢鐢佃В璐ㄤ负閰告�э紝浜岀敳閱氱洿鎺ョ噧鏂欑數姹犵殑璐熸瀬鍙嶅簲
涓?/p>
锛屼竴涓簩鐢查啔鍒嗗瓙缁忚繃鐢靛寲瀛︽哀鍖栵紝鍙互浜х敓
涓數瀛愮殑鑳介噺锛?
璇ョ數姹犵殑鐞嗚杈撳嚭鐢靛帇涓?/p>
1.20V
锛岃兘閲忓瘑搴?/p>
E =