1
绗竴绔?/p>
姒傜巼璁虹殑鍩烘湰姒傚康
涓�銆侀�夋嫨棰?/p>
1
锛庡皢涓�鏋氱‖甯佽繛鎶涗袱娆★紝鍒欐闅忔満璇曢獙鐨勬牱鏈┖闂翠负锛?/p>
锛?/p>
A
锛?/p>
{
锛堟锛屾锛?/p>
锛?/p>
锛堝弽锛屽弽锛?/p>
锛?/p>
锛堜竴姝ｄ竴鍙嶏級
}
B.{(
鍙嶏紝姝?/p>
)
锛?/p>
锛堟锛屽弽锛?/p>
锛?/p>
锛堟锛屾锛?/p>
锛?/p>
锛堝弽锛屽弽锛?/p>
}
C
锛?/p>
{
涓�娆℃闈紝涓ゆ姝ｉ潰锛屾病鏈夋闈?/p>
}
D.{
鍏堝緱姝ｉ潰锛屽厛寰楀弽闈?/p>
}
2.
璁?/p>
A
锛?/p>
B
涓轰换鎰忎袱涓簨浠讹紝鍒欎簨浠?/p>
(AUB)(
飦?/p>
-AB)
琛ㄧず锛?/p>
锛?/p>
A
锛庡繀鐒朵簨浠?/p>
B
锛?/p>
A
涓?/p>
B
鎭版湁涓�涓彂鐢?/p>
C
锛庝笉鍙兘浜嬩欢
D
锛?/p>
A
涓?/p>
B
涓嶅悓鏃跺彂鐢?/p>
3
锛庤
A
锛?/p>
B
涓洪殢鏈轰簨浠讹紝鍒欎笅鍒楀悇寮忎腑姝ｇ‘鐨勬槸锛?/p>
锛?/p>
.
A.P(AB)=P(A)P(B)
B.P(A-B)=P(A)
锛?/p>
P(B)
C.
)
(
)
(
B
A
P
B
A
P
飥?/p>
飥?/p>
D.P(A+B)=P(A)+P(B)
4.
璁?/p>
A,B
涓洪殢鏈轰簨浠?/p>
,
鍒欎笅鍒楀悇寮忎腑涓嶈兘鎭掓垚绔嬬殑鏄?/p>
( ).
A.P(A
锛?/p>
B)=P(A)
锛?/p>
P(AB)
B.P(AB)=P(B)P(A|B),
鍏朵腑
P(B)>0
C.P(A+B)=P(A)+P(B)
D.P(A)+P(
A
)=1
5.
鑻?/p>
飦?/p>
飩?/p>
AB
锛屽垯涓嬪垪鍚勫紡涓敊璇殑鏄紙
锛?/p>
.
A
锛?/p>
0
)
(
飩?/p>
AB
P
B.
1
)
(
飩?/p>
AB
P
C.P(A+B)=P(A)+P(B)
D.P(A-B)
飩?/p>
P(A)
6.
鑻?/p>
飦?/p>
飩?/p>
AB
,
鍒?/p>
( ).
A. A,B
涓哄绔嬩簨浠?/p>
B.
B
A
飥?/p>
C.
飦?/p>
飥?/p>
B
A
D.P(A-B)
飩?/p>
P(A)
7.
鑻?/p>
,
B
A
飪?/p>
鍒欎笅闈㈢瓟妗堥敊璇殑鏄?/p>
( ).
A.
飥?/p>
飥?/p>
B
P
A
P
飩?/p>
)
(
B.
飥?/p>
飥?/p>
0
A
-
B
P
飩?/p>