绗?/p>
1
绔?/p>
缁?/p>
璁?/p>
涔?/p>
棰?/p>
涓�銆侀棶绛旈
1.
浠�涔堟槸鏁版嵁缁撴瀯锛?/p>
2.
鍥涚被鍩烘湰鏁版嵁缁撴瀯鐨勫悕绉颁笌鍚箟銆?/p>
3.
绠楁硶鐨勫畾涔変笌鐗规�с�?/p>
4.
绠楁硶鐨勬椂闂村鏉傚害銆?/p>
5.
鏁版嵁绫诲瀷鐨勬蹇点�?/p>
6.
绾挎�х粨鏋勪笌闈炵嚎鎬х粨鏋勭殑宸埆銆?/p>
7.
闈㈠悜瀵硅薄绋嬪簭璁捐璇█鐨勭壒鐐广�?/p>
8.
鍦ㄩ潰鍚戝璞＄▼搴忚璁′腑锛岀被鐨勪綔鐢ㄦ槸浠�涔堬紵
9.
鍙傛暟浼犻�掔殑涓昏鏂瑰紡鍙婄壒鐐广�?/p>
10.
鎶借薄鏁版嵁绫诲瀷鐨勬蹇点�?/p>
浜屻�佸垽鏂
1.
绾挎�х粨鏋勫彧鑳界敤椤哄簭缁撴瀯鏉ュ瓨鏀撅紝闈炵嚎鎬х粨鏋勫彧鑳界敤闈為『搴忕粨鏋勬潵瀛樻斁銆?/p>
2.
绠楁硶灏辨槸绋嬪簭銆?/p>
3.
鍦ㄩ珮绾ц瑷�锛堝
C
銆佹垨
PASCAL
锛変腑锛屾寚閽堢被鍨嬫槸鍘熷瓙绫诲瀷銆?/p>
涓夈�佽绠椾笅鍒楃▼搴忔涓?/p>
X=X+1
鐨勮鍙ラ搴?/p>
for(i=1;i<=n;i++)
for(j=1;j<=i;j++)
for(k=1;k<=j;k++)
x=x+1;
[
鎻愮ず
]
锛?/p>
i=1
鏃讹細
1
= (1+1)脳
1/2
= (1+1
2
)/2
i=2
鏃讹細
1+2
= (1+2)脳
2/2
= (2+2
2
)/2
i=3
鏃讹細
1+2+3
= (1+3)脳
3/2
= (3+3
2
)/2
鈥?/p>
i=n
鏃讹細
1+2+3+鈥︹�?n
= (1+n)脳
n/2
= (n+n
2
)/2
f(n) = [ (1+2+3+鈥︹�?n) + (1
2
+ 2
2
+ 3
2
+ 鈥︹�?nbsp;+ n
2
) ] / 2
=[ (1+n)n/2 + n(n+1)(2n+1)/6 ] / 2