銆婅绠楁満甯哥敤绠楁硶涓庣▼搴忚璁℃渚嬫暀绋嬨�?/p>
涔犻瑙ｇ瓟鎻愯
涔犻
1
1-1
鍒嗘暟鍒嗚В绠楁硶鎻忚堪
鎶婄湡鍒嗘暟
a/b
鍒嗚В涓鸿嫢骞蹭釜鍒嗘瘝涓烘暣鏁板垎瀛愪负鈥?/p>
1
鈥濈殑鍩冨強鍒嗘暟涔嬪拰锛?/p>
锛?/p>
1
锛?/p>
瀵绘壘骞惰緭鍑哄皬浜?/p>
a/b
鐨勬渶澶у焹鍙婂垎鏁?/p>
1/c
锛?/p>
锛?/p>
2
锛?/p>
鑻?/p>
c>900000000
锛屽垯閫�鍑猴紱
锛?/p>
3
锛?/p>
鑻?/p>
c
鈮?/p>
900000000
锛屾妸宸?/p>
a/b-1/c
鏁寸悊涓哄垎鏁?/p>
a/b
锛岃嫢
a/b
涓哄焹鍙婂垎鏁帮紝鍒欒緭
鍑哄悗缁撴潫銆?/p>
锛?/p>
4
锛?/p>
鑻?/p>
a/b
涓嶄负鍩冨強鍒嗘暟锛屽垯缁х画锛?/p>
1
锛?/p>
銆?/p>
锛?/p>
2
锛?/p>
銆?/p>
锛?/p>
3
锛?/p>
銆?/p>
璇曟弿杩颁互涓婄畻娉曘�?/p>
瑙ｏ細璁?/p>
)
(
int
a
b
d
飥?/p>
(
杩欓噷
int(x)
琛ㄧず鍙栨鏁?/p>
x
鐨勬暣鏁?/p>
)
锛屾敞鎰忓埌
1
飥?/p>
飥?/p>
飥?/p>
d
a
b
d
锛屾湁
)
1
(
)
1
(
1
1
飥?/p>
飥?/p>
飥?/p>
飥?/p>
飥?/p>
飥?/p>
d
b
b
d
a
d
b
a
绠楁硶鎻忚堪锛氫护
c=d+1
锛屽垯
input (a,b)
while(1)
{c=int(b/a)+1;
if(c>900000000) return;
else
{ print(1/c+);
a=a*c-b;
b=b*c; // a,b
杩唬锛屼负閫夋嫨涓嬩竴涓垎姣嶄綔鍑嗗
if(a==1)
{ print(1/b);return;}
}
}
1-2
姹傚嚭浠ヤ笅绋嬪簭娈垫墍浠ｈ〃绠楁硶鐨勬椂闂村鏉傚害
锛?/p>
1
锛?/p>
m=0;
for(k=1;k<=n;k++)