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1. ¼õС£¬¼õС£¬Í¬Àë×ÓЧӦ£»2. 1.0?10-3 mol/L£»3. H3O+£¬OH-£»4. KaKb = Kw£»5.

Ka1Ka2£»6. ¼õС£¬Ï½µ£»7. CH3CH2CH2COOH£¬1.30?10£­5£»8. <5£¬5?7£¬>7£»9. »ù±¾²»±ä£¬¸üÇ¿£»10. NaCN > NaAc > NaNO2£»11. [Fe(H2O)6]£¬[Fe(H2O)4(OH)2]£»12. ±äÉ«·¶Î§£¬ËáÉ«ºÍ¼îÉ«µÄ»ìºÏÉ«£»13. ¼õС£¬c?Ka/c£»14. Ka2£¬Ka2£»15. 0.1 mol/L£¬0.1£»16. Ëá¼î£¬NH3 +

3+

+

H2O = NH4+ + OH-£»17. 4.4?8.0£»18. 4.8£»19. 9.0£»20. Ëá¼îÐÔ£¬ËáʽÐÎÌ壬¼îʽÐÎÌ壬0.1£¬10£¬2£»21. 1010£»22. 1.8?10-4£»23. µÎ¶¨Í»Ô¾·¶Î§£¬ÑÕÉ«±ä»¯ÊÇ·ñÒ×Óڹ۲죻24. ¸ß£¬¶à£»25. Õ­£»26. 3.4£¬2.4?4.4£»27. ÀíÂÛ±äÉ«µã£»28. ¶èÐÔȾÁÏ£¬Ö¸Ê¾¼Á£»29. ˫ָʾ¼Á£»30. »¯Ñ§¼ÆÁ¿µã£»31. ÈÜÒºµÄpH£¬Ìå»ý£¬µÎ¶¨ÇúÏߣ»32. Ç¿Ëá»òÇ¿¼î£¬Å¨¶È£¬»¯Ñ§¼ÆÁ¿£»33. cKa?10?8£¬

2Ka1/Ka2?10£»34. ÄÜÌṩÖÊ×ÓµÄÎïÖÊ£¬ÄܽÓÊÜÖÊ×ÓµÄÎïÖÊ£¬Ka?Kb = Kw£»35. Æ«¸ß£¬²»±ä¡£

5¶þ. ÕýÎóÅжÏÌâ

1. ?£»2. ?£»3. ?£»4. ?£»5. ?£»6. ?£»7. ?£»8. ?£»9. ?£»10. ?£»11. ?£»12. ?£»13. ?£»14. ?£»15. ?£»16. ?£»17. ?£»18. ?£»19. ?£»20. ?£»21. ?£»22. ?£»23. ?£»24. ?£»25. ?£»26. ?£»27. ?£»28. ?¡£ Èý. µ¥Ñ¡Ìâ

1. D£»2. A£»3. B£»4. D£»5. C£»6. A£»7. A£»8. D£»9. A£»10. A£»11. A£»12. B£»13. C£»14. D£»15. A£»16. C£»17. D£»18. A£»19. B£»20. D£»21. B£»22. A£»23. A£»24. A£»25. D£»26. B£»27. C£»28. A£»29. D£»30. A£»31. A£»32. B£»33. A£»34. A£»35. D£»36. D£»37. C£»38. D£»39. B£»40. C£»41. B£»42. B£»43. A£»44. D£»45. B¡£ ËÄ. ¼ÆËãÌâ 1. [H?]?0.30?6.4?10?7?4.4?10[H]0.010??4mol/L

2. ¸ù¾Ý?µÄ¶¨Ò壺0.042?K??£¬[H+] = 4.2?10-4 [mol/L]

?5(4.2?10?4)2?40.010?4.2?10?5?1.8?10

?4[H]?1.8?10cNaAc??0.010?4.2?10mol/L

?0.0500mol/L

2.05?(22.99?12.01?2?1.008?3?16.00?2)0.500[H]?Ka?cacb?1.8?10?50.010.05?3.6?10?6mol/L

pH = 5.44

3. 1?10?10?1?10?14?5cNH4Cl0.51.77?10

cNH4Cl?0.088mol/L

0.088?0.3?(14.01+1.008?4+35.45) = 1.4 g 4. [H?]?0.02?4.2?10?7?9.2?10?5

?5

[HCO]??30.02?9.2?10(9.2?10)?9.2?10?52?5?4.2?10?7?7?5?4.2?10?9.2?10?5.6?10?11= 9.1?10 mol/L

-5

[CO2?3]?0.02?4.2?10(9.2?10)?9.2?10?52?5?7?5.6?10?7?11?5?4.2?10?9.2?10?5.6?10?11= 5.5?10 mol/L

-11

5. É裺[H+] = 6.5?10-5ʱ£¬NaAcµÄŨ¶ÈΪx mol/L

6.5?10?5?1.76?10?50.2?xx

6.5x = 0.352 ¨C 1.76x, x = 0.043 mol/L

0.043?(22.99+16.00+1.008)?1.0 = 1.7 g 6. 0.5000?(40.08+12.01+16.00?3) = 5.005?10-3 mol

É裺NaOHÈÜÒºµÄŨ¶ÈΪx mol/L

5.005?10-3?2 = x?1.010?0.05000 ¨C 0.00620x x = 0.2312 mol/L

HClÈÜÒºµÄŨ¶È= 0.2289 mol/L

7. Na2CO3% = 0.1000?0.01500?(22.99?2 + 12.01 + 16.00?3)?0.3400?100% = 46.76%

NaHCO3% = 0.1000?(0.03600 ¨C 0.01500)?(22.99 + 1.008 + 12.01 + 16.00?3)?0.3400?100%

= 51.89%

0.2262134.08. 2MnO4- + 5C2O42- +16H+ = 2Mn2+ + 10CO2? + 8H2O

cKMnO4??5?2?0.04150?0.01627mol/L

MnO4- + 5Fe2- + 8H+ = Mn2+ + 5Fe3+ + 4H2O

0.01627?10?3?5?56.85?4.625?10?3g/mL

9. H2SO4 + 2NaOH = Na2SO4 + 2H2O

mH2SO4%?0.1340?0.01540?2?250.0025.00?98.03?1.125?100%?89.91%

10. CaCO3 + 2HCl = CaCl2 + H2CO3£¬ ¼ÓÈÈÖó·Ð£ºH2CO3 = CO2? + H2O

HCl + NaOH = NaCl + H2O

mCaCO3%?(0.2500?0.02500?0.2000?0.00584)?2?100.1?0.3000?100%?84.78%

mCaO%?(0.2500?0.02500?0.2000?0.00584)?2?56.08?0.3000?100%?47.50%

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